MatematikMathematics

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1

Question 1

[1 mark] Sekeping kad nombor tertulis 61 407. Nyatakan nilai tempat bagi digit yang bergaris bawah.A number card shows 61 407. State the place value of the underlined digit.

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• Hundreds (ratus) [1]: in 61 407 the 4 is in the hundreds place1

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For the teacher: Remembering, low difficulty, Unit 1, standard 1.1.2

Textbook p. 4

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Question 2

[2 marks] Hitung 4 205 × 18.Calculate 4 205 × 18.

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• 4 205 × 10 = 42 050 and 4 205 × 8 = 33 640 [1]1
• 42 050 + 33 640 = 75 690 [1]1

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For the teacher: Applying, low difficulty, Unit 1, standard 1.6.4

Textbook p. 34

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Question 3

[3 marks] Hitung 615 − 235 + 115. Tulis jawapan dalam bentuk termudah.Calculate 615 − 235 + 115. Write the answer in the simplest form.

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• Work from left to right: 615 − 235 = 565 − 235 = 335 [1]1
• 335 + 115 [1]1
• 445 [1]1

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For the teacher: Applying, low difficulty, Unit 2, standard 2.1.4

Textbook p. 81

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Question 4

[2 marks] Harga sebuah basikal ialah RM680. Rizal membayar wang pendahuluan RM150. Baki harga dibayar dengan 5 ansuran bulanan yang sama banyak. Berapakah jumlah satu ansuran?A bicycle costs RM680. Rizal pays a deposit of RM150. The rest of the price is paid in 5 equal monthly instalments. How much is one instalment?

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• RM680 − RM150 = RM530 [1]1
• RM530 ÷ 5 = RM106 [1]1

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For the teacher: Applying, medium difficulty, Unit 3, standard 3.7.1

Textbook p. 129

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Question 5

[2 marks] Sebuah bas bertolak pada pukul 0830 dan tiba pada pukul 1155. Hitung tempoh perjalanan bas itu, dalam jam dan minit.A bus leaves at 0830 hours and arrives at 1155 hours. Calculate the duration of the journey, in hours and minutes.

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• 0830 to 1130 is 3 hours; 1130 to 1155 is 25 minutes [1]1
• 3 hours 25 minutes [1]1

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For the teacher: Applying, low difficulty, Unit 4, standard 4.2.1

Textbook p. 143

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Question 6

[2 marks] Setiap sesi latihan koir mengambil masa 2 jam 50 minit. Hitung jumlah masa bagi 3 sesi latihan itu, dalam jam dan minit.Each choir practice takes 2 hours 50 minutes. Calculate the total time for 3 practices, in hours and minutes.

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• 3 × 2 h = 6 h and 3 × 50 min = 150 min [1]1
• 150 min = 2 h 30 min, so 8 hours 30 minutes [1]1

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For the teacher: Applying, medium difficulty, Unit 4, standard 4.5.1

Textbook p. 152

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Question 7

[2 marks] Hitung 6 kg 40 g − 2 kg 780 g. Nyatakan jawapan dalam kg dan g.Calculate 6 kg 40 g − 2 kg 780 g. State the answer in kg and g.

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• 6 040 g − 2 780 g = 3 260 g (or regroup 5 kg 1 040 g − 2 kg 780 g) [1]1
• 3 kg 260 g [1]1

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For the teacher: Applying, low difficulty, Unit 5, standard 5.2.2

Textbook p. 186

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Question 8

[2 marks] Rajah 1 menunjukkan sebuah kuboid. Hitung isi padu kuboid itu.Diagram 1 shows a cuboid. Calculate the volume of the cuboid.

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• Volume = length × width × height = 8 × 5 × 6 [1]1
• 240 cm³ [1] (accept 240 cubic cm; no unit or a wrong unit loses this mark)1

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For the teacher: Applying, low difficulty, Unit 6, standard 6.4.1

Textbook p. 210

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Question 9

[2 marks] Sebuah kereta menggunakan 8 ℓ petrol untuk menempuh jarak 96 km. Pada kadar yang sama, berapakah jarak yang dapat ditempuh dengan 15 ℓ petrol?A car uses 8 ℓ of petrol to travel 96 km. At the same rate, how far can it travel with 15 ℓ of petrol?

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• 96 ÷ 8 = 12 km for 1 ℓ [1]1
• 15 × 12 = 180 km [1]1

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For the teacher: Applying, medium difficulty, Unit 7, standard 7.3.1

Textbook p. 223

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Question 10

[1 mark] Rajah 2 menunjukkan beberapa titik pada satah Cartes. Nyatakan koordinat titik N.Diagram 2 shows some points on a Cartesian plane. State the coordinates of point N.

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• (2, 6) [1] (x first, then y)1

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For the teacher: Remembering, low difficulty, Unit 7, standard 7.1.1

Textbook p. 216

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Question 11

[2 marks] Carta palang dalam Rajah 3 menunjukkan bilangan pengunjung ke pusat sumber sekolah pada lima hari. Hitung beza antara bilangan pengunjung pada hari yang paling ramai dengan hari yang paling sedikit.The bar chart in Diagram 3 shows the number of visitors to the school resource centre on five days. Calculate the difference between the number of visitors on the busiest day and on the quietest day.

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• Busiest day Friday 60, quietest day Wednesday 20 [1]1
• 60 − 20 = 40 visitors [1]1

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For the teacher: Understanding, low difficulty, Unit 8, standard 8.1.2

Textbook p. 236

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Question 12

[3 marks] Jadual 1 menunjukkan warna kegemaran 60 orang murid. Bilangan murid yang memilih kuning tidak ditunjukkan. Hitung peratusan murid yang memilih kuning.

Warna	Merah	Biru	Hijau	Kuning
Bilangan murid	18	21	12	?

Table 1 shows the favourite colours of 60 pupils. The number of pupils who chose yellow is not shown. Calculate the percentage of pupils who chose yellow.

Colour	Red	Blue	Green	Yellow
Number of pupils	18	21	12	?

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• 18 + 21 + 12 = 51 [1]1
• Yellow: 60 − 51 = 9 pupils [1]1
• 9/60 × 100% = 15% [1]1

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For the teacher: Applying, medium difficulty, Unit 8, standard 8.2.1

Textbook p. 240

13

Question 13

[2 marks] Jumlah harga 3 buah beg sekolah yang sama dan sebuah kotak makanan RM38.50 ialah RM218.20. Berapakah harga sebuah beg sekolah?The total price of 3 similar school bags and a RM38.50 lunch box is RM218.20. What is the price of one school bag?

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• RM218.20 − RM38.50 = RM179.70 (the 3 bags) [1]1
• RM179.70 ÷ 3 = RM59.90 [1]1

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For the teacher: Analysing, high difficulty, Unit 3, standard 3.7.1

Textbook p. 129

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Question 14

Sekolah Kebangsaan Seri Mutiara mengadakan Hari Sukan. Rajah 4 ialah piktograf yang menunjukkan bilangan murid yang menyertai empat acara.Sekolah Kebangsaan Seri Mutiara holds its Sports Day. Diagram 4 is a pictograph showing the number of pupils who took part in four events.

[1 mark] (i)Berapakah bilangan murid yang menyertai lompat jauh?How many pupils took part in the long jump?

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• 3½ symbols × 6 = 21 pupils [1]1

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[1 mark] (ii)Acara yang manakah disertai oleh 12 orang murid?Which event had 12 pupils?

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• Shot put (2 symbols × 6 = 12) [1]1

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[1 mark] (iii)Hitung jumlah murid yang menyertai keempat-empat acara.Calculate the total number of pupils in the four events.

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• 30 + 21 + 12 + 27 = 90 pupils [1]1

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For the teacher: Understanding, low difficulty, Unit 8, standard 8.1.2

Textbook p. 237

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Question 15

Pada Hari Sukan itu, acara lompat jauh bermula pada pukul 1:50 petang dan berlangsung selama 1 jam 40 minit. Majlis penyampaian hadiah bermula 45 minit selepas acara itu tamat.At the Sports Day, the long jump starts at 1:50 p.m. and lasts 1 hour 40 minutes. The prize-giving starts 45 minutes after the event ends.

[3 marks] Hitung masa majlis penyampaian hadiah bermula. Tulis jawapan dalam sistem 24 jam.At what time does the prize-giving start? Write the answer in the 24-hour system.

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• 1:50 p.m. = 1350 hours [1]1
• 1350 + 1 h 40 min = 1530 hours (event ends) [1]1
• 1530 + 45 min = 1615 hours [1]1

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For the teacher: Applying, medium difficulty, Unit 4, standard 4.2.1

Textbook p. 144

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Question 16

Nisbah bilangan pingat emas yang dimenangi Rumah Merah kepada bilangan pingat emas yang dimenangi Rumah Biru ialah 2 : 3. Rumah Merah memenangi 6 pingat emas.The ratio of the number of gold medals won by Red House to the number won by Blue House is 2 : 3. Red House wins 6 gold medals.

[2 marks] (i)Berapakah bilangan pingat emas yang dimenangi Rumah Biru?How many gold medals does Blue House win?

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• 6 ÷ 2 = 3 medals for 1 part [1]1
• 3 × 3 = 9 medals [1]1

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[1 mark] (ii)Hitung jumlah pingat emas yang dimenangi kedua-dua rumah itu.Calculate the total number of gold medals won by the two houses.

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• 6 + 9 = 15 medals [1]1

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For the teacher: Applying, medium difficulty, Unit 7, standard 7.2.1

Textbook p. 220

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Question 17

Jadual 2 menunjukkan mata yang diperoleh empat rumah sukan. Jumlah mata ialah 500. Rumah Hijau mendapat 15 mata kurang daripada Rumah Biru.

Rumah	Merah	Biru	Hijau	Kuning
Mata	128	135	?	?

Table 2 shows the points won by four sports houses. The total number of points is 500. Green House gets 15 points fewer than Blue House.

House	Red	Blue	Green	Yellow
Points	128	135	?	?

[3 marks] Hitung mata yang diperoleh Rumah Kuning.Calculate the points won by Yellow House.

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• Green: 135 − 15 = 120 points [1]1
• Red + Blue + Green = 128 + 135 + 120 = 383 [1]1
• Yellow: 500 − 383 = 117 points [1]1

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For the teacher: Analysing, high difficulty, Unit 8, standard 8.2.1

Textbook p. 241

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Question 18

Ahli Kelab Sains menjalankan beberapa aktiviti. Rajah 5 menunjukkan air dalam dua buah silinder penyukat.Members of the Science Club carry out some activities. Diagram 5 shows the water in two measuring cylinders.

[1 mark] (i)Nyatakan isi padu air dalam silinder penyukat P, dalam mℓ.State the volume of water in measuring cylinder P, in mℓ.

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• 650 mℓ [1]1

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[1 mark] (ii)Nyatakan isi padu air dalam silinder penyukat Q, dalam ℓ dan mℓ.State the volume of water in measuring cylinder Q, in ℓ and mℓ.

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• 1 150 mℓ = 1 ℓ 150 mℓ [1]1

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[1 mark] (iii)Berapakah isi padu air, dalam mℓ, yang perlu dituang ke dalam silinder P supaya isi padunya sama dengan silinder Q?What volume of water, in mℓ, must be poured into cylinder P so that it holds the same volume as cylinder Q?

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• 1 150 − 650 = 500 mℓ [1]1

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For the teacher: Remembering, low difficulty, Unit 5, standard 5.3.1

Textbook p. 188

19

Question 19

Tinggi sebatang anak pokok kacang ialah 14.6 cm. Pada minggu pertama anak pokok itu tumbuh 2.75 cm dan pada minggu kedua tumbuh 3.9 cm.A bean seedling is 14.6 cm tall. In the first week it grows 2.75 cm and in the second week it grows 3.9 cm.

[3 marks] Hitung tinggi anak pokok itu pada akhir minggu kedua.Calculate the height of the seedling at the end of the second week.

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• 14.6 + 2.75 = 17.35 cm at the end of the first week [1]1
• 17.35 + 3.9 [1]1
• 21.25 cm [1]1

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For the teacher: Applying, low difficulty, Unit 2, standard 2.2.1

Textbook p. 86

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Question 20

Rajah 6 menunjukkan sebuah kotak yang mengandungi 5 biji batu yang sama jisim. Jisim kotak kosong ialah 200 g.Diagram 6 shows a box holding 5 stones of the same mass. The mass of the empty box is 200 g.

[3 marks] Hitung jisim, dalam g, sebiji batu itu.Calculate the mass, in g, of one stone.

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• 3 kg 450 g = 3 450 g [1]1
• 3 450 − 200 = 3 250 g (the 5 stones) [1]1
• 3 250 ÷ 5 = 650 g [1]1

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For the teacher: Applying, medium difficulty, Unit 5, standard 5.2.2

Textbook p. 186

21

Question 21

Kelab Sains menerima wang RM150. Kelab itu membeli 12 buah bikar dengan harga RM8.50 sebuah. Baki wang digunakan untuk membeli 5 buah kanta pembesar yang sama harga.The Science Club receives RM150. The club buys 12 beakers at RM8.50 each. The rest of the money is used to buy 5 magnifying glasses of the same price.

[3 marks] Berapakah harga sebuah kanta pembesar?What is the price of one magnifying glass?

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• 12 × RM8.50 = RM102 [1]1
• RM150 − RM102 = RM48 [1]1
• RM48 ÷ 5 = RM9.60 [1]1

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For the teacher: Analysing, high difficulty, Unit 3, standard 3.7.1

Textbook p. 129

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