Practice paper, not an official KPM paper

Matematik Tahun 5

Ujian Akhir Sesi AkademikEnd of Academic Session Test

MatematikMathematics

Darjah 5, 1 jam 15 minit / 1 hour 15 minutes, 50 marks

Nama / Name

Kelas / Class

Tarikh / Date

Markah / Marks: / 50

Instructions

Jawab semua soalan.Answer all questions.
Tulis jawapan dan tunjukkan langkah-langkah penting.Write the answer and show the important steps.
Bahagian A: 26 markah. Bahagian B: 24 markah.Section A: 26 marks. Section B: 24 marks.

Answer schemes are in English (DLP).

Practice shows answers as you go. Exam times you and hides answers until you submit.

Bahagian ASection A

26 marks

Jawab semua soalan.Answer all questions.

Question 1

Rajah 1 menunjukkan satu nombor dalam jadual nilai tempat. Nyatakan nilai digit bagi digit 3.Diagram 1 shows a number in a place-value chart. State the digit value of the digit 3.

Place-value chart: hundred thousands 8, ten thousands 3, thousands 7, hundreds 0, tens 6, ones 2 — Rajah 1Diagram 1

[1 mark]

Show answerHide answer

30 000 (the number is 837 062)

The 3 is in the ten thousands place: digit value 30 000 [1]1

Tick each point you got.

For the teacher: Remembering, low difficulty, Unit 1, standard 1.1.2

Textbook p. 5

Question 2

Nyatakan nombor bulat yang terbesar yang apabila dibundarkan kepada puluh ribu yang terdekat menjadi 640 000.State the largest whole number that becomes 640 000 when rounded off to the nearest ten thousand.

[1 mark]

Show answerHide answer

644 999 (645 000 would round up to 650 000, so 644 999 is the largest)

644 999 [1]1

Tick each point you got.

For the teacher: Applying, high difficulty, Unit 1, standard 1.4.1

Textbook p. 17

Question 3

3 746 × 28 =

[2 marks]

Show answerHide answer

104 888 (check: 3 746 × 28 is about 3 700 × 30 = 111 000, close to 104 888)

Working: 3 746 × 8 = 29 968 and 3 746 × 20 = 74 920 [1]1
104 888 [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 1, standard 1.6.3

Textbook p. 29

Question 4

(84 000 − 48 000) ÷ 12 + 3 250 =

[2 marks]

Show answerHide answer

Brackets first: 84 000 − 48 000 = 36 000, then 36 000 ÷ 12 = 3 000 [1]1
3 000 + 3 250 = 6 250 [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 1, standard 1.7.1

Textbook p. 49

Question 5

4.75 × 6 =

[2 marks]

Show answerHide answer

475 × 6 = 2 850 (or 4 × 6 = 24 and 0.75 × 6 = 4.5) [1]1
28.5 (28.50) [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 2, standard 2.2.3

Textbook p. 76

Question 6

RM800 000 − ______ = RM364 275.80

[2 marks]

Show answerHide answer

RM435 724.20 (check: RM435 724.20 + RM364 275.80 = RM800 000)

The missing amount = RM800 000 − RM364 275.80 [1]1
RM435 724.20 [1]1

Tick each point you got.

For the teacher: Applying, medium difficulty, Unit 3, standard 3.1.2

Textbook p. 93

Question 7

Rajah 2 menunjukkan harga sebuah tin biskut raya. Sebuah kedai membeli 24 tin biskut itu. Berapakah jumlah harganya?Diagram 2 shows the price of a festival biscuit tin. A shop buys 24 of these tins. What is the total price?

Price tag: festival biscuit tin RM17.60 — Rajah 2Diagram 2

[2 marks]

Show answerHide answer

RM422.40 (24 × 1 760 sen = 42 240 sen)

24 × RM17.60 [1]1
RM422.40 [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 3, standard 3.1.3

Textbook p. 95

Question 8

Rajah 3 menunjukkan tarikh mula dan tarikh tamat Pesta Buku sekolah pada tahun 2024. Berapakah tempoh pesta itu, dalam hari? Hitung hari pertama dan hari terakhir.Diagram 3 shows the start date and the end date of a school Book Fair in 2024. What is the duration of the fair, in days? Count both the first day and the last day.

Start: 20 February 2024. End: 12 March 2024 — Rajah 3Diagram 3

[2 marks]

Show answerHide answer

22 days

2024 is a leap year (2024 ÷ 4 = 506), so February has 29 days: 20 to 29 February = 29 − 20 + 1 = 10 days [1]1
1 to 12 March = 12 days; 10 + 12 = 22 days [1]1

Tick each point you got.

For the teacher: Applying, medium difficulty, Unit 4, standard 4.1.1 (ii)

Textbook p. 125

Question 9

1.2 km + 350 m + 4 500 cm = ______ m

[2 marks]

Show answerHide answer

1.2 km = 1 200 m and 4 500 cm = 45 m [1]1
1 200 + 350 + 45 = 1 595 m [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 5, standard 5.1.3

Textbook p. 182

Question 10

Encik Samad membeli sebuah motosikal berharga RM7 400. Dia membayar 35% daripada harga itu sebagai bayaran pendahuluan. Berapakah baki yang masih perlu dibayar?Encik Samad buys a motorcycle for RM7 400. He pays 35% of the price as a down payment. How much does he still have to pay?

[2 marks]

Show answerHide answer

RM4 810 (or 65% of RM7 400 = RM4 810)

35% of RM7 400 = 35/100 × RM7 400 = RM2 590 [1]1
RM7 400 − RM2 590 = RM4 810 [1]1

Tick each point you got.

For the teacher: Applying, medium difficulty, Unit 2, standard 2.3.2

Textbook p. 82

Question 11

Rajah 4 menunjukkan bilangan buku cerita yang dibaca oleh 11 orang murid dalam sebulan. Apakah median bagi data itu?Diagram 4 shows the number of storybooks read by 11 pupils in a month. What is the median of the data?

Frequency table: 1 book 1 pupil, 2 books 4 pupils, 3 books 2 pupils, 4 books 3 pupils, 5 books 1 pupil — Rajah 4Diagram 4

[2 marks]

Show answerHide answer

Arrange the 11 values in order: 1, 2, 2, 2, 2, 3, 3, 4, 4, 4, 5; the middle value is the 6th [1]1
Median = 3 books [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 8, standard 8.2.1

Textbook p. 256

Question 12

Rajah 5 menunjukkan jisim sebiji durian dan sebiji betik. Nyatakan nisbah jisim betik kepada jumlah jisim kedua-dua buah itu.Diagram 5 shows the mass of a durian and of a papaya. State the ratio of the mass of the papaya to the total mass of the two fruits.

A durian of mass 1.5 kg and a papaya of mass 600 g — Rajah 5Diagram 5

[3 marks]

Show answerHide answer

600 : 2 100, which is 2 : 7

Change to the same unit: 1.5 kg = 1 500 g [1]1
Total mass = 1 500 + 600 = 2 100 g [1]1
600 : 2 100 [1] (2 : 7 is also accepted)1

Tick each point you got.

For the teacher: Analysing, high difficulty, Unit 7, standard 7.2.1

Textbook p. 239

Question 13

Rajah 6 menunjukkan gabungan sebuah segi empat sama dengan sebuah segi empat tepat. Luas segi empat sama itu ialah 64 cm². Hitung luas seluruh bentuk itu.Diagram 6 shows a square joined to a rectangle. The area of the square is 64 cm². Calculate the area of the whole shape.

A square of area 64 cm2 on the left and a rectangle 5 cm high joined to its right side at the bottom; the whole bottom edge is 19 cm — Rajah 6Diagram 6

[3 marks]

Show answerHide answer

119 cm²

Side of the square = 8 cm (8 × 8 = 64) [1]1
Length of the rectangle = 19 − 8 = 11 cm [1]1
Area of the whole shape = 64 + (11 × 5) = 64 + 55 = 119 cm² [1]1

Tick each point you got.

For the teacher: Analysing, high difficulty, Unit 6, standard 6.3.2

Textbook p. 224

Bahagian BSection B

24 marks

Jawab semua soalan.Answer all questions.

Question 14

Rajah 7 menunjukkan bahan yang dibeli untuk gerai kek di pesta sekolah.Diagram 7 shows the ingredients bought for the cake stall at the school fair.

Flour: 12 packets of 750 g each; sugar: 8 packets of 1 kg each; butter: 5 packets of 250 g each — Rajah 7Diagram 7

[1 mark] (a)Hitung jumlah jisim tepung itu, dalam kg.Calculate the total mass of the flour, in kg.

Show answerHide answer

12 × 750 g = 9 000 g = 9 kg [1]1

Tick each point you got.

[2 marks] (b)Sebanyak 3 kg 250 g tepung digunakan untuk membuat kek. Berapakah jisim tepung yang tinggal? Beri jawapan dalam kg dan g.3 kg 250 g of the flour is used to bake cakes. What is the mass of flour left? Give the answer in kg and g.

Show answerHide answer

5 kg 750 g (5 750 g)

9 kg − 3 kg 250 g [1]1
5 kg 750 g [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 5, standard 5.2.2

Textbook p. 192

Question 15

Rajah 8 menunjukkan kedudukan tiga buah gerai di pesta sekolah pada satah Cartes.Diagram 8 shows the positions of three stalls at the school fair on a Cartesian plane.

Cartesian plane from 0 to 10: games stall G at (2, 6), food stall F at (8, 6), prize stall P at (8, 2) — Rajah 8Diagram 8

[1 mark] (a)Nyatakan koordinat Gerai Hadiah, P.State the coordinates of the Prize stall, P.

Show answerHide answer

(8, 2) [1]1

Tick each point you got.

[2 marks] (b)Mei berjalan dari Gerai Permainan, G, lurus ke Gerai Makanan, F, kemudian lurus ke Gerai Hadiah, P. Berapakah jumlah jarak, dalam unit, yang dilalui oleh Mei?Mei walks from the Games stall, G, straight to the Food stall, F, and then straight to the Prize stall, P. What is the total distance, in units, that Mei walks?

Show answerHide answer

10 units

G to F: 8 − 2 = 6 units across; F to P: 6 − 2 = 4 units down [1]1
6 + 4 = 10 units [1]1

Tick each point you got.

For the teacher: Applying, medium difficulty, Unit 7, standard 7.1.1

Textbook p. 237

Question 16

Rajah 9 menunjukkan resit bagi barang hiasan yang dibeli untuk pesta sekolah. Jumlah bagi paket cawan kertas tidak ditunjukkan.Diagram 9 shows the receipt for decorations bought for the school fair. The amount for the packets of paper cups is not shown.

Receipt: balloons 30 at RM0.80 = RM24.00; paper cups 12 packets at RM3.75 = ?; ribbon 8 rolls at RM6.45 = RM51.60 — Rajah 9Diagram 9

[1 mark] (a)Hitung jumlah bagi paket cawan kertas.Calculate the amount for the packets of paper cups.

Show answerHide answer

12 × RM3.75 = RM45.00 [1]1

Tick each point you got.

[1 mark] (b)Hitung jumlah bayaran bagi ketiga-tiga barang itu.Calculate the total bill for the three items.

Show answerHide answer

RM24.00 + RM45.00 + RM51.60 = RM120.60 [1]1

Tick each point you got.

[1 mark] (c)Cikgu membayar dengan RM150. Berapakah bakinya?The teacher pays with RM150. How much is the change?

Show answerHide answer

RM150 − RM120.60 = RM29.40 [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 3, standard 3.1.3

Textbook p. 95

Question 17

Cikgu Aziz dan Puan Mala bercakap tentang kereta mainan yang dijual di pesta sekolah.
Cikgu Aziz: “Pembekal menghantar 7 karton kereta mainan. Setiap karton mengandungi 1 250 buah kereta mainan.”
Puan Mala: “Pada hari Sabtu, 2 760 buah dijual. Pada hari Ahad, kami menjual 1 235 buah lebih daripada hari Sabtu.”
Berapakah bilangan kereta mainan yang masih tinggal selepas dua hari itu?Cikgu Aziz and Puan Mala talk about the toy cars sold at the school fair.
Cikgu Aziz: “The supplier sent 7 cartons of toy cars. Each carton has 1 250 toy cars.”
Puan Mala: “On Saturday, 2 760 were sold. On Sunday, we sold 1 235 more than on Saturday.”
How many toy cars are left after the two days?

[3 marks]

Show answerHide answer

1 995 toy cars

Total toy cars = 7 × 1 250 = 8 750 [1]1
Sunday = 2 760 + 1 235 = 3 995; sold in two days = 2 760 + 3 995 = 6 755 [1]1
Left = 8 750 − 6 755 = 1 995 [1]1

Tick each point you got.

For the teacher: Analysing, high difficulty, Unit 1, standard 1.9.2

Textbook p. 51

Question 18

Hana berkata, “Saya fikir satu nombor. Saya darabkan nombor itu dengan 6, kemudian saya tolak 2 450. Jawapannya ialah 5 650.” Nombor itu ialah bilangan syiling dalam tabung simpanan Hana.Hana says, “I think of a number. I multiply the number by 6, then I subtract 2 450. The answer is 5 650.” The number is the number of coins in Hana's savings tin.

[2 marks] (a)Cari nombor itu.Find the number.

Show answerHide answer

1 350 coins (check: 1 350 × 6 − 2 450 = 5 650)

Work backwards: 5 650 + 2 450 = 8 100 [1]1
8 100 ÷ 6 = 1 350 [1]1

Tick each point you got.

[1 mark] (b)Tabung simpanan Farid mempunyai 2 kali ganda bilangan syiling dalam tabung Hana. Berapakah jumlah syiling dalam kedua-dua tabung itu?Farid's savings tin has twice as many coins as Hana's tin. How many coins are there in the two tins altogether?

Show answerHide answer

1 350 + 2 × 1 350 = 4 050 [1]1

Tick each point you got.

For the teacher: Applying, medium difficulty, Unit 1, standard 1.8.2

Textbook p. 39

Question 19

Rajah 10 menunjukkan masa yang diambil oleh Kelas 5 Cerdik dalam lawatan ke sebuah bank.Diagram 10 shows the time taken by Class 5 Cerdik on a visit to a bank.

Bus journey 1.6 hours; tour inside the bank 2 hours 45 minutes — Rajah 10Diagram 10

[1 mark] (a)Tukarkan 1.6 jam kepada jam dan minit.Change 1.6 hours to hours and minutes.

Show answerHide answer

0.6 × 60 = 36, so 1.6 hours = 1 hour 36 minutes [1]1

Tick each point you got.

[2 marks] (b)Hitung jumlah masa lawatan itu, dalam jam dan minit.Calculate the total time of the visit, in hours and minutes.

Show answerHide answer

4 hours 21 minutes

1 hour 36 minutes + 2 hours 45 minutes = 3 hours 81 minutes [1]1
4 hours 21 minutes [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 4, standard 4.3.2 (i)

Textbook p. 142

Question 20

Cikgu Jamal menyimpan wang dalam akaun simpanan seperti yang ditunjukkan dalam Rajah 11. Dia tidak mengeluarkan sebarang wang, termasuk faedah.Cikgu Jamal saves money in a savings account as shown in Diagram 11. He does not withdraw any money, including the interest.

Savings account: opening balance RM12 000.00, interest rate 1.5% a year, withdrawals none — Rajah 11Diagram 11

[1 mark] (a)Hitung faedah yang diterima pada akhir tahun pertama.Calculate the interest earned at the end of the first year.

Show answerHide answer

1.5% of RM12 000 = RM180 [1]1

Tick each point you got.

[2 marks] (b)Hitung faedah yang diterima pada akhir tahun kedua.Calculate the interest earned at the end of the second year.

Show answerHide answer

RM182.70

Balance at the start of the second year = RM12 000 + RM180 = RM12 180 [1]1
1.5% of RM12 180 = RM182.70 [1]1

Tick each point you got.

For the teacher: Applying, medium difficulty, Unit 3, standard 3.3.2

Textbook p. 106

Question 21

Rajah 12 menunjukkan bilangan murid yang membuat simpanan di kaunter bank sekolah dalam seminggu.Diagram 12 shows the number of pupils who saved at the school bank counter in one week.

Pupils who saved: Monday 24, Tuesday 18, Wednesday 30, Thursday 21, Friday 27 — Rajah 12Diagram 12

[2 marks] (a)Hitung min bilangan murid yang membuat simpanan setiap hari.Calculate the mean number of pupils who saved each day.

Show answerHide answer

24 pupils

24 + 18 + 30 + 21 + 27 = 120 [1]1
120 ÷ 5 = 24 pupils [1]1

Tick each point you got.

[1 mark] (b)Pada min yang sama, berapakah jumlah murid yang dijangka membuat simpanan dalam 20 hari persekolahan?At the same mean, how many pupils are expected to save in 20 school days?

Show answerHide answer

24 × 20 = 480 pupils [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 8, standard 8.2.1

Textbook p. 255

Test specification (JSU)

Unit	Remembering	Understanding	Applying	Analysing	Evaluating	Creating	Items	marks
1. Whole Numbers and Operations	1 (1)	–	4 (8)	1 (3)	–	–	6	12
2. Fractions, Decimals and Percentages	–	–	2 (4)	–	–	–	2	4
3. Money	–	–	4 (10)	–	–	–	4	10
4. Time	–	–	2 (5)	–	–	–	2	5
5. Length, Mass and Volume of Liquid	–	–	2 (5)	–	–	–	2	5
6. Space	–	–	–	1 (3)	–	–	1	3
7. Coordinates, Ratio and Proportion	–	–	1 (3)	1 (3)	–	–	2	6
8. Data Handling	–	–	2 (5)	–	–	–	2	5
Total	1 (1)	0 (0)	17 (40)	3 (9)	0 (0)	0 (0)	21	50

Each cell shows items (marks).