Practice paper, not an official KPM paper

Matematik Tahun 5

Ujian Akhir Sesi AkademikEnd of Academic Session Test

MatematikMathematics

Darjah 5, 1 jam 15 minit / 1 hour 15 minutes, 50 marks

Nama / Name

Kelas / Class

Tarikh / Date

Markah / Marks: / 50

Instructions

Jawab semua soalan.Answer all questions.
Tulis jawapan dan tunjukkan langkah-langkah penting. Ini boleh membantu anda mendapatkan markah.Write the answer and show the important steps. This can help you to get marks.
Bahagian A: 26 markah. Bahagian B: 24 markah.Section A: 26 marks. Section B: 24 marks.
Rajah yang mengiringi soalan tidak dilukis mengikut skala kecuali dinyatakan.The diagrams accompanying the questions are not drawn to scale unless stated.

Answer schemes are in English (DLP).

Practice shows answers as you go. Exam times you and hides answers until you submit.

Bahagian ASection A

26 marks

Jawab semua soalan.Answer all questions.

Question 1

Rajah 1 menunjukkan satu nombor yang ditulis sebagai hasil tambah nilai digit.Diagram 1 shows a number written as a sum of digit values.

A number partitioned as 700 000 + 50 000 + 8 000 + 90 + 3 — Rajah 1Diagram 1

[1 mark] Apakah nilai tempat bagi digit 5 dalam nombor itu?What is the place value of the digit 5 in the number?

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The number is 700 000 + 50 000 + 8 000 + 90 + 3 = 758 093. The digit 5 is in the ten thousands place.

Ten thousands (puluh ribu) [1]1

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For the teacher: Remembering, low difficulty, Unit 1, standard 1.1.2

Textbook p. 5

Question 2

[1 mark] Nyatakan satu nombor yang lebih besar daripada 400 000 dan menjadi 400 000 apabila dibundarkan kepada ratus ribu yang terdekat. Digit ribu bagi nombor itu ialah 9.State a number that is greater than 400 000 and becomes 400 000 when rounded off to the nearest hundred thousand. The thousands digit of the number is 9.

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Numbers from 350 000 to 449 999 round to 400 000. To be greater than 400 000 the number must be 400 001 to 449 999, and its thousands digit must be 9: 409 xxx, 419 xxx, 429 xxx, 439 xxx or 449 xxx.

Any number from 400 001 to 449 999 whose thousands digit is 9, for example 419 640 [1]1

Tick each point you got.

For the teacher: Analysing, high difficulty, Unit 1, standard 1.4.1

Textbook p. 17

Question 3

[2 marks] 9 × 1 512 = ______ Beri jawapan sebagai nombor bercampur dalam bentuk termudah.9 × 1 512 = ______ Give the answer as a mixed number in its simplest form.

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9 × 1712 = 15312 = 514 = 12 34

Change to an improper fraction and multiply: 9 × 1712 = 15312 [1]1
Simplest form: 514 = 12 34 [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 2, standard 2.1.1

Textbook p. 68

Question 4

[2 marks] Sebuah bekas mengandungi 840 g tepung. 58 daripada tepung itu digunakan. Nyatakan jisim tepung yang digunakan sebagai pecahan daripada 1 kg dalam bentuk termudah.A container holds 840 g of flour. 58 of the flour is used. Write the mass of flour used as a fraction of 1 kg, in its simplest form.

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525 ÷ 1 000 = 5251000; dividing top and bottom by 25 gives 2140.

58 × 840 = 525 g [1]1
525 g = 5251000 kg = 2140 kg [1] (so 2140 of 1 kg)1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 2, standard 2.1.1

Textbook p. 67

Question 5

[2 marks] Bundarkan 7.384 kepada dua tempat perpuluhan dan 5.296 kepada satu tempat perpuluhan. Kemudian, cari jumlah kedua-dua nombor yang dibundarkan itu.Round off 7.384 to two decimal places and 5.296 to one decimal place. Then find the sum of the two rounded numbers.

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The third decimal place of 7.384 is 4 (round down). The second decimal place of 5.296 is 9 (round the 2 up to 3).

7.384 ≈ 7.38 and 5.296 ≈ 5.3 [1]1
7.38 + 5.3 = 12.68 [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 2, standard 2.2.1

Textbook p. 71

Question 6

Rajah 2 menunjukkan tiga bar yang sama saiz. Setiap bar dibahagikan kepada 10 bahagian yang sama.Diagram 2 shows three bars of the same size. Each bar is divided into 10 equal parts.

Three bars of 10 equal parts: the first two fully shaded and the third with 7 parts shaded — Rajah 2Diagram 2

[2 marks] Nyatakan bahagian berlorek sebagai nombor bercampur, kemudian ubahkannya kepada peratus.Write the shaded part as a mixed number, then change it to a percentage.

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Two whole bars and 7 of the 10 parts of the third bar are shaded. 2 710 = 2.7 = 270%.

2 710 [1]1
270% [1]1

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For the teacher: Applying, medium difficulty, Unit 2, standard 2.3.1

Textbook p. 81

Question 7

Price tag: pen RM2.65 each — Rajah 3Diagram 3

[2 marks] Rajah 3 menunjukkan harga sebatang pen. Cikgu Salmah membeli 15 batang pen yang sama dan membayar dengan RM50. Hitung baki wang Cikgu Salmah.Diagram 3 shows the price of a pen. Cikgu Salmah buys 15 of these pens and pays RM50. Calculate her balance.

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RM50 − (15 × RM2.65) = RM50 − RM39.75 = RM10.25

15 × RM2.65 = RM39.75 [1]1
RM50 − RM39.75 = RM10.25 [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 3, standard 3.2.1

Textbook p. 99

Question 8

[2 marks] 1 25 jam + 35 minit = ______ jam ______ minit1 25 hours + 35 minutes = ______ hours ______ minutes

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1 25 hours = 60 + 25 × 60 = 60 + 24 = 84 minutes [1]1
84 + 35 = 119 minutes = 1 hour 59 minutes [1]1

Tick each point you got.

For the teacher: Applying, medium difficulty, Unit 4, standard 4.3.1 (i)

Textbook p. 141

Question 9

[2 marks] 2.45 kg + 875 g = ______ g

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2.45 kg = 2 450 g [1]1
2 450 + 875 = 3 325 g [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 5, standard 5.2.2

Textbook p. 191

Question 10

Measuring jug with the water level at 1 200 mℓ — Rajah 4Diagram 4

[2 marks] Rajah 4 menunjukkan air di dalam sebuah jag. 38 daripada air itu dituang keluar. Berapakah isi padu air, dalam mℓ, yang tinggal di dalam jag itu?Diagram 4 shows the water in a jug. 38 of the water is poured out. What volume of water, in mℓ, is left in the jug?

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Or: 58 of 1 200 = 750 mℓ.

38 × 1 200 = 450 mℓ poured out [1]1
1 200 − 450 = 750 mℓ [1]1

Tick each point you got.

For the teacher: Applying, medium difficulty, Unit 5, standard 5.3.4

Textbook p. 205

Question 11

Jadual dalam Rajah 5 menunjukkan bilangan buku yang dipinjam oleh 30 orang murid dalam seminggu.The table in Diagram 5 shows the number of books borrowed by 30 pupils in a week.

Frequency table: 1 to 6 books borrowed by 4, 7, 9, 5, 3 and 2 pupils — Rajah 5Diagram 5

[2 marks] Nyatakan mod dan julat bagi data itu.State the mode and the range of the data.

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Mode = 3 books (the highest frequency, 9 pupils) [1]1
Range = 6 − 1 = 5 [1]1

Tick each point you got.

For the teacher: Understanding, low difficulty, Unit 8, standard 8.2.1

Textbook p. 254

Question 12

Rajah 6 menunjukkan adunan gula dan tepung dengan jisim 4.5 kg. Nisbah jisim gula kepada jisim tepung ialah 3 : 2.Diagram 6 shows a mixture of sugar and flour with a mass of 4.5 kg. The ratio of the mass of sugar to the mass of flour is 3 : 2.

A bar of 5 equal units, 3 for sugar and 2 for flour, with a total of 4.5 kg — Rajah 6Diagram 6

[3 marks] Hitung jisim gula, dalam g, di dalam adunan itu.Calculate the mass of the sugar, in g, in the mixture.

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Flour = 2 × 900 = 1 800 g, and 2 700 + 1 800 = 4 500 g.

4.5 kg = 4 500 g; sugar is 3 of 5 units (sugar : mixture = 3 : 5) [1]1
4 500 ÷ 5 = 900 g for 1 unit [1]1
3 × 900 = 2 700 g [1]1

Tick each point you got.

For the teacher: Analysing, high difficulty, Unit 7, standard 7.2.1

Textbook p. 239

Question 13

Rajah 7 menunjukkan gabungan sebuah kubus dan sebuah kuboid. Lebar kuboid itu sama dengan sisi kubus.Diagram 7 shows the combination of a cube and a cuboid. The breadth of the cuboid is the same as the edge of the cube.

A cube of edge 5 cm joined to a cuboid of length x cm, breadth 5 cm and height 4 cm — Rajah 7Diagram 7

[3 marks] Isi padu gabungan bentuk itu ialah 325 cm³. Hitung nilai x.The volume of the combined shape is 325 cm³. Calculate the value of x.

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Check: 10 × 5 × 4 = 200 cm³ and 125 + 200 = 325 cm³.

Cube: 5 × 5 × 5 = 125 cm³ [1]1
Cuboid: 325 − 125 = 200 cm³ [1]1
200 ÷ (5 × 4) = 10, so x = 10 [1]1

Tick each point you got.

For the teacher: Applying, high difficulty, Unit 6, standard 6.4.1

Textbook p. 226

Bahagian BSection B

24 marks

Jawab semua soalan.Answer all questions.

Question 14

Rajah 8 menunjukkan kad resipi sebuah kedai roti untuk satu adunan kek mentega.Diagram 8 shows a bakery recipe card for one batch of butter cake.

Recipe card: flour 0.875 kg, sugar 0.450 kg, butter 0.325 kg — Rajah 8Diagram 8

[1 mark] (a)Hitung jumlah jisim, dalam kg, ketiga-tiga bahan itu untuk satu adunan.Calculate the total mass, in kg, of the three ingredients for one batch.

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0.875 + 0.450 + 0.325 = 1.650 kg [1]1

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[1 mark] (b)Kak Zah membuat 3 adunan. Hitung jumlah jisim, dalam kg, tepung yang digunakan.Kak Zah bakes 3 batches. Calculate the total mass, in kg, of flour used.

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3 × 0.875 = 2.625 kg [1]1

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[1 mark] (c)Dia mempunyai 4 kg tepung pada mulanya. Berapakah jisim tepung, dalam kg, yang tinggal?She had 4 kg of flour at first. What mass of flour, in kg, is left?

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4 − 2.625 = 1.375 kg [1] (follow through from (b))1

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For the teacher: Applying, low difficulty, Unit 2, standard 2.4.1

Textbook p. 86

Question 15

Carta pai dalam Rajah 9 menunjukkan jenis kuih dan roti yang dijual di jualan kek sekolah.The pie chart in Diagram 9 shows the kinds of cakes and pastries sold at the school cake sale.

Pie chart: curry puff 35%, doughnut 20%, brownie not shown, muffin 15% — Rajah 9Diagram 9

[1 mark] (a)Berapakah peratus kuih dan roti yang dijual ialah brownis?What percentage of the items sold are brownies?

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100% − (35% + 20% + 15%) = 30% [1]1

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[2 marks] (b)Sejumlah 800 biji kuih dan roti dijual. Berapakah bilangan karipap yang dijual lebih banyak daripada muffin?A total of 800 items were sold. How many more curry puffs than muffins were sold?

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Or: curry puffs 35% × 800 = 280, muffins 15% × 800 = 120, and 280 − 120 = 160.

35% − 15% = 20% [1]1
20% of 800 = 160 [1]1

Tick each point you got.

For the teacher: Applying, medium difficulty, Unit 8, standard 8.1.1

Textbook p. 252

Question 16

Rajah 10 menunjukkan perbualan antara Puan Rosnah dan Hadi tentang biskut di jualan kek sekolah.Diagram 10 shows the conversation between Puan Rosnah and Hadi about the cookies at the school cake sale.

Puan Rosnah made 80 tins of cookies costing RM360. Hadi says 75% of the tins were sold at RM6.50 a tin — Rajah 10Diagram 10

[1 mark] (a)Berapakah bilangan tin biskut yang dijual?How many tins of cookies were sold?

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75% of 80 = 60 tins [1]1

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[1 mark] (b)Berapakah jumlah jualan, dalam RM, tin yang dijual itu?What are the total sales, in RM, of the tins that were sold?

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60 × RM6.50 = RM390 [1] (follow through from (a))1

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[1 mark] (c)Hitung keuntungan, dalam RM, Puan Rosnah daripada jualan itu selepas menolak kos membuat semua 80 tin.Calculate Puan Rosnah's profit, in RM, from these sales after taking away the cost of making all 80 tins.

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Profit = selling price − cost. The cost RM360 is for all 80 tins, as the picture says.

RM390 − RM360 = RM30 [1] (follow through from (b))1

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For the teacher: Applying, low difficulty, Unit 3, standard 3.5.1

Textbook p. 112

Question 17

A regular hexagon Q joined to a regular pentagon P, perimeter of the combined shape 63 cm — Rajah 11Diagram 11

[3 marks] Rajah 11 menunjukkan sebuah pentagon sekata P dan sebuah heksagon sekata Q yang bercantum pada satu sisi. Perimeter gabungan bentuk itu ialah 63 cm. Hitung perimeter, dalam cm, heksagon sekata Q.Diagram 11 shows a regular pentagon P and a regular hexagon Q joined along one side. The perimeter of the combined shape is 63 cm. Calculate the perimeter, in cm, of the regular hexagon Q.

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The shared side is inside the shape, so it is not part of the perimeter. Check: 9 × 7 = 63 cm.

Outer sides: 4 (pentagon) + 5 (hexagon) = 9 equal sides, the shared side is not counted [1]1
63 ÷ 9 = 7 cm for one side [1]1
6 × 7 = 42 cm [1]1

Tick each point you got.

For the teacher: Analysing, high difficulty, Unit 6, standard 6.5.1

Textbook p. 229

Question 18

Jadual dalam Rajah 12 menunjukkan mata yang dikumpulkan oleh tiga buah rumah sukan sepanjang tahun.The table in Diagram 12 shows the points collected by three sports houses during the year.

Table: Tuah 2 485; Jebat 368 more than Tuah; Lekir 295 fewer than Jebat — Rajah 12Diagram 12

[1 mark] (a)Berapakah bilangan mata Rumah Jebat?How many points did Jebat House collect?

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2 485 + 368 = 2 853 [1]1

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[2 marks] (b)Hitung jumlah mata ketiga-tiga rumah itu.Calculate the total points of the three houses.

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Lekir: 2 853 − 295 = 2 558 [1]1
2 485 + 2 853 + 2 558 = 7 896 [1] (follow through from (a))1

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For the teacher: Applying, medium difficulty, Unit 1, standard 1.9.2

Textbook p. 51

Question 19

Jadual dalam Rajah 13 menunjukkan atur cara pagi Hari Sukan.The table in Diagram 13 shows the morning programme of Sports Day.

Timetable: track events 8.15 a.m. to 10.05 a.m., break 10.05 to 10.35 a.m., field events 10.35 a.m. to 12.10 p.m. — Rajah 13Diagram 13

[1 mark] (a)Berapakah tempoh, dalam jam dan minit, acara balapan?What is the duration, in hours and minutes, of the track events?

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10.05 a.m. − 8.15 a.m. = 1 hour 50 minutes [1]1

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[1 mark] (b)Berapakah tempoh, dalam jam dan minit, acara padang?What is the duration, in hours and minutes, of the field events?

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12.10 p.m. − 10.35 a.m. = 1 hour 35 minutes [1]1

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[1 mark] (c)Acara balapan lebih lama berapa minit daripada acara padang?By how many minutes are the track events longer than the field events?

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1 hour 50 minutes − 1 hour 35 minutes = 15 minutes [1] (follow through from (a) and (b))1

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For the teacher: Applying, low difficulty, Unit 4, standard 4.3.2 (i)

Textbook p. 154

Question 20

Pada Hari Sukan, sebuah stesen air mempunyai 240 biji cawan kertas. Sebanyak 45% daripada cawan itu telah digunakan pada waktu pagi.On Sports Day, a water station has 240 paper cups. 45% of the cups were used in the morning.

[1 mark] (a)Berapakah bilangan cawan yang digunakan?How many cups were used?

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45% of 240 = 108 [1]1

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[2 marks] (b)Nyatakan bilangan cawan yang tinggal sebagai pecahan daripada 240 cawan dalam bentuk termudah.Write the number of cups left as a fraction of the 240 cups, in its simplest form.

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Or: 100% − 45% = 55% = 55100 = 1120.

240 − 108 = 132 cups left [1] (follow through from (a))1
132240 = 1120 [1]1

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For the teacher: Applying, medium difficulty, Unit 2, standard 2.3.2

Textbook p. 83

Question 21

Carta palang dalam Rajah 14 menunjukkan mata yang diperoleh Rumah Kasturi dalam lima acara. Skala menegak bermula pada 40 (ada sela pada paksi).The bar chart in Diagram 14 shows the points won by Kasturi House in five events. The vertical scale starts at 40 (the axis has a break).

Bar chart of points: Run 52, Jump 58, Throw 46, Relay 60, Tug of war 54 — Rajah 14Diagram 14

[1 mark] (a)Hitung jumlah mata yang diperoleh Rumah Kasturi dalam lima acara itu.Calculate the total points that Kasturi House won in the five events.

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52 + 58 + 46 + 60 + 54 = 270 [1]1

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[1 mark] (b)Hitung min mata bagi satu acara.Calculate the mean points for one event.

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270 ÷ 5 = 54 [1] (follow through from (a))1

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[1 mark] (c)Dalam acara keenam, Rumah Kasturi mahu min mata bagi enam acara menjadi 55. Berapakah mata yang diperlukan dalam acara keenam?In the sixth event, Kasturi House wants the mean points for the six events to be 55. How many points are needed in the sixth event?

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6 × 55 − 270 = 330 − 270 = 60 [1]1

Tick each point you got.

For the teacher: Applying, low difficulty, Unit 8, standard 8.2.1

Textbook p. 256

Test specification (JSU)

Unit	Remembering	Understanding	Applying	Analysing	Evaluating	Creating	Items	marks
1. Whole Numbers and Operations	1 (1)	–	1 (3)	1 (1)	–	–	3	5
2. Fractions, Decimals and Percentages	–	–	6 (14)	–	–	–	6	14
3. Money	–	–	2 (5)	–	–	–	2	5
4. Time	–	–	2 (5)	–	–	–	2	5
5. Length, Mass and Volume of Liquid	–	–	2 (4)	–	–	–	2	4
6. Space	–	–	1 (3)	1 (3)	–	–	2	6
7. Coordinates, Ratio and Proportion	–	–	–	1 (3)	–	–	1	3
8. Data Handling	–	1 (2)	2 (6)	–	–	–	3	8
Total	1 (1)	1 (2)	16 (40)	3 (7)	0 (0)	0 (0)	21	50

Each cell shows items (marks).