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Practice paper, not an official KPM paper
50
Ujian Akhir Sesi AkademikEnd of Academic Session Test

MatematikMathematics

Tingkatan 2, 2 jam / 2 hours, 100 marks
Nama / Name
Kelas / Class
Tarikh / Date
Markah / Marks:      / 100
Instructions
  1. Kertas soalan ini mengandungi tiga bahagian: Bahagian A, Bahagian B dan Bahagian C.This question paper consists of three sections: Section A, Section B and Section C.
  2. Jawab semua soalan.Answer all questions.
  3. Tunjukkan langkah-langkah penting dalam kerja mengira anda.Show your working. It may help you to get marks.
  4. Rajah yang mengiringi soalan tidak dilukis mengikut skala kecuali dinyatakan.The diagrams in this paper are not drawn to scale unless stated.
  5. Anda dibenarkan menggunakan kalkulator saintifik.You may use a scientific calculator.

Answer schemes are in English (DLP).

Practice shows answers as you go. Exam times you and hides answers until you submit.

Bahagian ASection A

20 marks
Jawab semua soalan. Setiap soalan diikuti oleh empat pilihan jawapan, A, B, C dan D. Pilih satu jawapan yang terbaik.Answer all questions. Each question is followed by four options, A, B, C and D. Choose the best answer.
1

Question 1

Jawatankuasa kebajikan sekolah menjual tiket derma. Bilangan tiket yang tinggal pada akhir hari pertama, kedua, ketiga dan keempat ialah 40, 34, 28 dan 22. Antara yang berikut, yang manakah ungkapan algebra bagi bilangan tiket yang tinggal pada akhir hari ke-n?The school welfare committee sells donation tickets. The numbers of tickets left at the end of the first, second, third and fourth days are 40, 34, 28 and 22. Which of the following is the algebraic expression for the number of tickets left at the end of day n?
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C
Each day 6 fewer tickets are left, so the expression starts with −6n. For n = 1 the value must be 40, so 46 − 6(1) = 40. Check n = 2: 46 − 12 = 34. (40 − 6n gives 34 for n = 1.)
For the teacher: Understanding, medium difficulty, Chapter 1, standard 1.3.1
Textbook p. 10
2

Question 2

Faktorkan selengkapnya 5x² − 20.Factorise 5x² − 20 completely.
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A
Take out the common factor first: 5x² − 20 = 5(x² − 4) = 5(x − 2)(x + 2). Option C is not completely factorised because (5x − 10) still has a common factor of 5.
For the teacher: Applying, low difficulty, Chapter 2, standard 2.2.2
Textbook p. 29
3

Question 3

Ringkaskan x² − 92x + 4 × x + 2x + 3.Simplify x² − 92x + 4 × x + 2x + 3.
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D
Factorise: x² − 9 = (x − 3)(x + 3) and 2x + 4 = 2(x + 2). Then (x − 3)(x + 3) / [2(x + 2)] × (x + 2)/(x + 3) = (x − 3)/2 after cancelling (x + 2) and (x + 3).
For the teacher: Analysing, high difficulty, Chapter 2, standard 2.3.2
Textbook p. 36
4

Question 4

Diberi y = √(x3) + 2. Ungkapkan x sebagai perkara rumus.Given y = √(x3) + 2, express x as the subject of the formula.
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B
Subtract 2: y − 2 = √(x/3). Square both sides: (y − 2)² = x/3. Multiply by 3: x = 3(y − 2)². Option C squares only the 3 and not the whole fraction under the root.
For the teacher: Applying, medium difficulty, Chapter 3, standard 3.1.2
Textbook p. 46
5

Question 5

Jumlah sudut pedalaman sebuah poligon ialah 2 160°. Berapakah bilangan sisi poligon itu?The sum of the interior angles of a polygon is 2 160°. How many sides does the polygon have?
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B
Sum = (n − 2) × 180°, so (n − 2) = 2 160 ÷ 180 = 12 and n = 14. (12 forgets to add the 2 back.)
For the teacher: Applying, low difficulty, Chapter 4, standard 4.2.1
Textbook p. 63
6

Question 6

Rajah 1 menunjukkan sebuah pentagon. Hitung sudut yang terbesar.Diagram 1 shows a pentagon. Calculate the largest angle.
Pentagon with interior angles 110 degrees, 130 degrees, x, 2x and 3x
Rajah 1Diagram 1
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D
Sum of interior angles of a pentagon = (5 − 2) × 180° = 540°. 110° + 130° + x + 2x + 3x = 540°, so 6x = 300° and x = 50°. The angles are 50°, 100° and 150°, so the largest is 3x = 150°.
For the teacher: Applying, medium difficulty, Chapter 4, standard 4.2.1
Textbook p. 64
7

Question 7

Sebuah sektor bulatan mempunyai jejari 6 cm dan sudut di pusat 210°. Hitung panjang lengkok sektor itu, dalam cm. [Guna π = 227]A sector of a circle has a radius of 6 cm and an angle of 210° at the centre. Calculate the arc length of the sector, in cm. [Use π = 227]
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A
Arc length = 210/360 × 2πr = 7/12 × 2 × 22/7 × 6 = 22 cm. (37.7 is the whole circumference, 15.7 is the arc for 150°, and 66 is the area of the sector.)
For the teacher: Applying, medium difficulty, Chapter 5, standard 5.3.3
Textbook p. 90
8

Question 8

Lilitan sebuah bulatan ialah 66 cm. Hitung jejari bulatan itu, dalam cm. [Guna π = 227]The circumference of a circle is 66 cm. Calculate the radius of the circle, in cm. [Use π = 227]
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C
C = 2πr, so r = 66 ÷ (2 × 22/7) = 66 × 7/44 = 10.5 cm. (21 is the diameter.)
For the teacher: Applying, low difficulty, Chapter 5, standard 5.3.1
Textbook p. 86
9

Question 9

Berapakah bilangan tepi sebuah prisma pentagon?How many edges does a pentagonal prism have?
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C
A pentagonal prism has two pentagonal bases with 5 edges each (10 edges) and 5 edges joining the bases. 10 + 5 = 15 edges.
For the teacher: Remembering, low difficulty, Chapter 6, standard 6.1.1
Textbook p. 101
10

Question 10

Rajah 2 menunjukkan sebuah kon dengan jejari 6 cm dan tinggi tegak 8 cm. Hitung isi padu kon itu, dalam cm³.Diagram 2 shows a cone with a radius of 6 cm and a vertical height of 8 cm. Calculate the volume of the cone, in cm³.
Cone with radius 6 cm and height 8 cm
Rajah 2Diagram 2
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B
V = 1/3 × π × 6² × 8 = 96π cm³. (288π forgets the factor 1/3; 120π uses the slant height 10 cm instead of the vertical height.)
For the teacher: Applying, medium difficulty, Chapter 6, standard 6.4.2
Textbook p. 113
11

Question 11

Cari titik tengah bagi garis lurus yang menyambungkan titik (−4, 7) dan titik (10, −1).Find the midpoint of the straight line joining the points (−4, 7) and (10, −1).
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A
Midpoint = ((−4 + 10)/2, (7 + (−1))/2) = (3, 3). (6, 6) forgets to divide by 2.
For the teacher: Applying, low difficulty, Chapter 7, standard 7.2.1
Textbook p. 133
12

Question 12

Hitung jarak antara titik (1, −2) dengan titik (9, 13).Calculate the distance between the points (1, −2) and (9, 13).
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D
Horizontal distance = 9 − 1 = 8; vertical distance = 13 − (−2) = 15. Distance = √(8² + 15²) = √289 = 17. (23 adds the two distances instead of using Pythagoras.)
For the teacher: Applying, low difficulty, Chapter 7, standard 7.1.3
Textbook p. 127
13

Question 13

Diberi fungsi f(x) = x² − 3x + 1. Cari nilai f(−2).Given the function f(x) = x² − 3x + 1, find the value of f(−2).
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B
f(−2) = (−2)² − 3(−2) + 1 = 4 + 6 + 1 = 11. (3 uses −2² = −4; −1 treats −3 × (−2) as −6.)
For the teacher: Understanding, low difficulty, Chapter 8, standard 8.1.2
Textbook p. 150
14

Question 14

Laju sebuah motosikal bertambah secara seragam daripada 5 m/s kepada 25 m/s dalam masa 8 s. Hitung pecutan motosikal itu, dalam m/s².The speed of a motorcycle increases uniformly from 5 m/s to 25 m/s in 8 s. Calculate the acceleration of the motorcycle, in m/s².
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C
Acceleration = change in speed ÷ time = (25 − 5) ÷ 8 = 2.5 m/s². (20 is the change in speed and was not divided by the time.)
For the teacher: Applying, medium difficulty, Chapter 9, standard 9.2.2
Textbook p. 181
15

Question 15

Cari kecerunan garis lurus yang melalui titik (−2, 5) dan titik (4, −7).Find the gradient of the straight line passing through the points (−2, 5) and (4, −7).
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A
m = (−7 − 5) ÷ (4 − (−2)) = −12 ÷ 6 = −2. The line goes down from left to right, so the gradient is negative.
For the teacher: Applying, low difficulty, Chapter 10, standard 10.1.2
Textbook p. 194
16

Question 16

Cari imej bagi titik (−3, 5) di bawah translasi 4−6.Find the image of the point (−3, 5) under the translation 4−6.
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D
Add the vector to the point: (−3 + 4, 5 + (−6)) = (1, −1).
For the teacher: Applying, low difficulty, Chapter 11, standard 11.2.2
Textbook p. 214
17

Question 17

Titik (4, −1) diputarkan 90° ikut arah jam pada pusat (1, 2). Cari koordinat imej titik itu.The point (4, −1) is rotated 90° clockwise about the centre (1, 2). Find the coordinates of its image.
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A
Relative to the centre (1, 2) the point is (3, −3). A 90° clockwise turn maps (a, b) to (b, −a), giving (−3, −3). Add the centre back: (−3 + 1, −3 + 2) = (−2, −1). (−3, −3) forgets to add the centre; (4, 5) turns anticlockwise.
For the teacher: Applying, high difficulty, Chapter 11, standard 11.4.3
Textbook p. 228
18

Question 18

Min bagi lima nombor ialah 12. Apabila nombor yang keenam ditambah, min bagi enam nombor itu menjadi 14. Cari nilai nombor yang keenam.The mean of five numbers is 12. When a sixth number is added, the mean of the six numbers becomes 14. Find the value of the sixth number.
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C
Sum of five numbers = 5 × 12 = 60. Sum of six numbers = 6 × 14 = 84. Sixth number = 84 − 60 = 24.
For the teacher: Analysing, high difficulty, Chapter 12, standard 12.1.2
Textbook p. 255
19

Question 19

Sebuah kotak mengandungi 7 lencana merah, 5 lencana biru dan 8 lencana hijau. Sebuah lencana dipilih secara rawak. Cari kebarangkalian bahawa lencana yang dipilih bukan berwarna biru.A box contains 7 red badges, 5 blue badges and 8 green badges. One badge is chosen at random. Find the probability that the badge chosen is not blue.
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D
n(S) = 7 + 5 + 8 = 20. P(blue) = 5/20 = 1/4, so P(not blue) = 1 − 1/4 = 3/4. (Or 15/20 = 3/4.)
For the teacher: Applying, low difficulty, Chapter 13, standard 13.3.2
Textbook p. 288
20

Question 20

Sebuah peti mengandungi 6 keping kad hijau dan 4 keping kad kuning. Berapakah bilangan kad kuning yang perlu ditambah supaya kebarangkalian memilih sekeping kad kuning menjadi 12?A box contains 6 green cards and 4 yellow cards. How many yellow cards must be added so that the probability of choosing a yellow card becomes 12?
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B
After adding k yellow cards: (4 + k)/(10 + k) = 1/2, so 8 + 2k = 10 + k and k = 2. Check: 6 yellow out of 12 cards = 1/2.
For the teacher: Analysing, high difficulty, Chapter 13, standard 13.4.1
Textbook p. 291

Bahagian BSection B

20 marks
Jawab semua soalan. Tunjukkan langkah-langkah penting dalam kerja mengira anda.Answer all questions. Show the important steps in your working.
21

Question 21

Jadual 1 menunjukkan bilangan kerusi dalam empat baris pertama sebuah dewan sekolah. Bilangan kerusi bertambah dengan cara yang sama bagi setiap baris.
Baris1234
Bilangan kerusi14182226
Table 1 shows the number of seats in the first four rows of a school hall. The number of seats increases in the same way for every row.
Row1234
Number of seats14182226
[1 mark] (a)Nyatakan pola bilangan kerusi itu dalam perkataan.State the pattern of the number of seats in words.
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[1 mark] (b)Cari bilangan kerusi dalam baris ke-6.Find the number of seats in the 6th row.
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[2 marks] (c)Tulis ungkapan algebra bagi bilangan kerusi dalam baris ke-n, dan seterusnya cari bilangan kerusi dalam baris ke-15.Write an algebraic expression for the number of seats in row n, and hence find the number of seats in row 15.
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For the teacher: Understanding, low difficulty, Chapter 1, standard 1.3.2
Textbook p. 11
22

Question 22

Rajah 3 menunjukkan sebuah pentagon PQRST.Diagram 3 shows a pentagon PQRST.
Pentagon PQRST with interior angles 105, 112, 98, 125 degrees and x at T
Rajah 3Diagram 3
[1 mark] (a)Hitung jumlah sudut pedalaman sebuah pentagon.Calculate the sum of the interior angles of a pentagon.
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[1 mark] (b)Cari nilai x.Find the value of x.
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[2 marks] (c)Setiap sudut pedalaman sebuah poligon sekata ialah 156°. Cari bilangan sisi poligon itu.Each interior angle of a regular polygon is 156°. Find the number of sides of the polygon.
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For the teacher: Applying, low difficulty, Chapter 4, standard 4.2.1
Textbook p. 64
23

Question 23

Rajah 4 menunjukkan titik K(−3, −1) dan titik L(2, 11) pada suatu satah Cartes.Diagram 4 shows the points K(−3, −1) and L(2, 11) on a Cartesian plane.
Points K(-3, -1) and L(2, 11) joined by a straight line
Rajah 4Diagram 4
[2 marks] (a)Hitung jarak KL.Calculate the distance KL.
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[1 mark] (b)Cari koordinat titik tengah bagi KL.Find the coordinates of the midpoint of KL.
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[1 mark] (c)L ialah titik tengah bagi garis lurus KN. Cari koordinat N.L is the midpoint of the straight line KN. Find the coordinates of N.
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For the teacher: Applying, medium difficulty, Chapter 7, standard 7.1.3
Textbook p. 128
24

Question 24

Rajah 5 menunjukkan garis lurus PQ yang memotong paksi-x di P(−4, 0) dan paksi-y di Q(0, 10).Diagram 5 shows the straight line PQ, which cuts the x-axis at P(−4, 0) and the y-axis at Q(0, 10).
Straight line through P(-4, 0) and Q(0, 10)
Rajah 5Diagram 5
[2 marks] (a)Hitung kecerunan garis lurus PQ.Calculate the gradient of the straight line PQ.
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[2 marks] (b)Titik R(2, k) terletak pada garis lurus PQ. Cari nilai k.The point R(2, k) lies on the straight line PQ. Find the value of k.
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For the teacher: Applying, medium difficulty, Chapter 10, standard 10.1.5
Textbook p. 198
25

Question 25

Dalam karnival sekolah, sebuah kotak cabutan bertuah mengandungi 20 keping tiket: 4 keping tiket emas, 6 keping tiket perak dan 10 keping tiket biasa. Sekeping tiket dicabut secara rawak.At a school carnival, a lucky-draw box contains 20 tickets: 4 gold tickets, 6 silver tickets and 10 plain tickets. One ticket is drawn at random.
[1 mark] (a)Cari kebarangkalian bahawa tiket yang dicabut ialah tiket perak.Find the probability that the ticket drawn is a silver ticket.
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[1 mark] (b)Cari kebarangkalian bahawa tiket yang dicabut bukan tiket biasa.Find the probability that the ticket drawn is not a plain ticket.
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[2 marks] (c)Ravi berkata, "Kebarangkalian mencabut tiket emas ialah 13 kerana terdapat tiga jenis tiket." Adakah Ravi betul? Berikan alasan anda dengan pengiraan.Ravi says, "The probability of drawing a gold ticket is 13 because there are three kinds of ticket." Is Ravi correct? Give a reason with a calculation.
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For the teacher: Evaluating, high difficulty, Chapter 13, standard 13.3.2
Textbook p. 288

Bahagian CSection C

60 marks
Jawab semua soalan. Tunjukkan langkah-langkah penting dalam kerja mengira anda.Answer all questions. Show the important steps in your working.
26

Question 26

[2 marks] (a)Kembangkan
(i) 5x(2x − 3)
(ii) (3y − 4)(y + 2)Expand
(i) 5x(2x − 3)
(ii) (3y − 4)(y + 2)
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[3 marks] (b)Faktorkan selengkapnya
(i) 12ab − 8b²
(ii) 2x² − 50
(iii) x² − 5x − 24Factorise completely
(i) 12ab − 8b²
(ii) 2x² − 50
(iii) x² − 5x − 24
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[2 marks] (c)Ringkaskan 3x − 2 + 4x + 2.Simplify 3x − 2 + 4x + 2.
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[3 marks] (d)Luas sebuah taman sekolah yang berbentuk segi empat tepat ialah (x² + 7x + 12) m². Lebarnya ialah (x + 3) m.
(i) Cari panjang taman itu dalam sebutan x.
(ii) Hitung perimeter taman itu, dalam m, apabila x = 5.The area of a rectangular school garden is (x² + 7x + 12) m². Its width is (x + 3) m.
(i) Find the length of the garden in terms of x.
(ii) Calculate the perimeter of the garden, in m, when x = 5.
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For the teacher: Applying, low difficulty, Chapter 2, standard 2.2.2
Textbook p. 29
27

Question 27

[2 marks] (a)Sebuah pusat tuisyen mengenakan yuran pendaftaran RM40 dan RM18 bagi setiap sesi kelas. Tulis satu rumus bagi jumlah yuran, F, dalam RM, bagi n sesi kelas dan hitung nilai F apabila n = 12.A tuition centre charges a registration fee of RM40 and RM18 for each class session. Write a formula for the total fee, F, in RM, for n class sessions and calculate the value of F when n = 12.
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[3 marks] (b)Tenaga kinetik, K, sebuah objek berjisim m yang bergerak dengan laju v diberi oleh K = 12mv².
(i) Ungkapkan v sebagai perkara rumus.
(ii) Hitung nilai v apabila K = 250 dan m = 5.The kinetic energy, K, of an object of mass m moving at speed v is given by K = 12mv².
(i) Express v as the subject of the formula.
(ii) Calculate the value of v when K = 250 and m = 5.
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[3 marks] (c)Diberi T = 2√(k − 5).
(i) Ungkapkan k dalam sebutan T.
(ii) Hitung nilai k apabila T = 6.Given T = 2√(k − 5).
(i) Express k in terms of T.
(ii) Calculate the value of k when T = 6.
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[2 marks] (d)Rumus untuk menukar suhu daripada °C kepada °F ialah F = 95C + 32.
(i) Ungkapkan C sebagai perkara rumus.
(ii) Hitung suhu, dalam °C, apabila F = 95.The formula for changing a temperature from °C to °F is F = 95C + 32.
(i) Express C as the subject of the formula.
(ii) Calculate the temperature, in °C, when F = 95.
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For the teacher: Applying, low difficulty, Chapter 3, standard 3.1.2
Textbook p. 46
28

Question 28

Rajah 6 menunjukkan bentuk sebuah papan tanda kelab sekolah. Papan tanda itu terdiri daripada sebuah segi empat tepat berukuran 22 cm × 14 cm dan dua buah semibulatan berdiameter 14 cm. [Guna π = 227]Diagram 6 shows the shape of a school club signboard. The signboard is made up of a rectangle measuring 22 cm × 14 cm and two semicircles of diameter 14 cm. [Use π = 227]
Rectangle 22 cm by 14 cm with a semicircle on each 14 cm side
Rajah 6Diagram 6
[3 marks] (a)Hitung perimeter papan tanda itu, dalam cm.Calculate the perimeter of the signboard, in cm.
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[3 marks] (b)Hitung luas papan tanda itu, dalam cm².Calculate the area of the signboard, in cm².
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[4 marks] (c)Aini mempunyai 88 cm jalur kayu untuk membuat bingkai sebuah papan tanda. Dia boleh membengkokkannya menjadi bentuk dalam Rajah 6 atau menjadi sebuah bulatan. Bentuk manakah yang patut dipilih Aini supaya papan tandanya mempunyai luas yang lebih besar? Tunjukkan pengiraan anda.Aini has 88 cm of wooden strip to make the frame of a signboard. She can bend it into the shape in Diagram 6 or into a circle. Which shape should Aini choose so that her signboard has the larger area? Show your calculations.
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For the teacher: Evaluating, medium difficulty, Chapter 5, standard 5.3.4
Textbook p. 92
29

Question 29

[2 marks] (a)Fungsi g ditakrifkan oleh g(x) = 2x + 5 bagi domain {−2, 0, 1, 4}.
(i) Nyatakan julat fungsi itu.
(ii) Cari objek yang mempunyai imej 7.The function g is defined by g(x) = 2x + 5 for the domain {−2, 0, 1, 4}.
(i) State the range of the function.
(ii) Find the object that has image 7.
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[4 marks] (b)Rajah 7 menunjukkan graf fungsi y = x² − 2x − 3 bagi −2 ≤ x ≤ 4. Daripada graf itu, cari
(i) nilai y apabila x = 2,
(ii) nilai x apabila y = 0,
(iii) nilai x apabila y = 5,
(iv) nilai minimum bagi y.Diagram 7 shows the graph of the function y = x² − 2x − 3 for −2 ≤ x ≤ 4. From the graph, find
(i) the value of y when x = 2,
(ii) the values of x when y = 0,
(iii) the values of x when y = 5,
(iv) the minimum value of y.
Graph of y = x squared minus 2x minus 3 for x from -2 to 4, a U-shaped curve with lowest point (1, -4)
Rajah 7Diagram 7
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[4 marks] (c)Sebuah kedai fotostat mengenakan caj tetap RM5 dan RM0.20 bagi setiap halaman yang dicetak. Biar y ialah jumlah kos, dalam RM, untuk mencetak x halaman.
(i) Tulis fungsi yang memberi y dalam sebutan x.
(ii) Lengkapkan jadual nilai bagi x = 0, 10, 20 dan 30.
(iii) Nyatakan bentuk graf fungsi itu.A photocopy shop charges a fixed fee of RM5 and RM0.20 for each page printed. Let y be the total cost, in RM, of printing x pages.
(i) Write a function that gives y in terms of x.
(ii) Complete a table of values for x = 0, 10, 20 and 30.
(iii) State the shape of the graph of the function.
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For the teacher: Applying, low difficulty, Chapter 8, standard 8.2.2
Textbook p. 158
30

Question 30

Rajah 8 menunjukkan segi tiga ABC dan segi tiga PQR pada suatu satah Cartes. Segi tiga PQR ialah imej bagi segi tiga ABC di bawah suatu putaran.Diagram 8 shows triangle ABC and triangle PQR on a Cartesian plane. Triangle PQR is the image of triangle ABC under a rotation.
Triangle ABC with A(1,1), B(5,1), C(1,4) and triangle PQR with P(1,-1), Q(1,-5), R(4,-1)
Rajah 8Diagram 8
[3 marks] (a)Segi tiga ABC ditranslasikan oleh −62. Nyatakan koordinat imej bagi A, B dan C.Triangle ABC is translated by −62. State the coordinates of the images of A, B and C.
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[3 marks] (b)Huraikan putaran yang memetakan segi tiga ABC kepada segi tiga PQR dengan lengkap.Describe in full the rotation that maps triangle ABC onto triangle PQR.
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[2 marks] (c)Adakah segi tiga ABC dan segi tiga PQR kongruen? Berikan alasan anda.Are triangle ABC and triangle PQR congruent? Give a reason.
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[2 marks] (d)Sebuah logo sekolah berbentuk oktagon sekata. Nyatakan peringkat simetri putaran dan sudut putaran terkecil yang memetakan logo itu kepada dirinya sendiri.A school logo is in the shape of a regular octagon. State the order of rotational symmetry and the smallest angle of rotation that maps the logo onto itself.
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For the teacher: Applying, medium difficulty, Chapter 11, standard 11.4.2
Textbook p. 224
31

Question 31

Jadual 2 menunjukkan masa, dalam minit, yang diambil oleh 40 orang murid untuk tiba di sekolah pada suatu pagi.
Masa (minit)1 – 1011 – 2021 – 3031 – 4041 – 50
Kekerapan6141253
Table 2 shows the time, in minutes, taken by 40 students to arrive at school one morning.
Time (minutes)1 – 1011 – 2021 – 3031 – 4041 – 50
Frequency6141253
[1 mark] (a)Nyatakan kelas mod.State the modal class.
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[3 marks] (b)Hitung min masa untuk tiba di sekolah, dalam minit.Calculate the mean time to arrive at school, in minutes.
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[2 marks] (c)Bilangan murid yang hadir ke kelas tambahan Matematik dalam tujuh minggu berturut-turut ialah
3, 4, 4, 5, 4, 6, 16
Hitung min dan median bagi data itu.The numbers of students attending an extra Mathematics class in seven consecutive weeks are
3, 4, 4, 5, 4, 6, 16
Calculate the mean and the median of the data.
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[4 marks] (d)Cikgu Rina berkata, "Purata kehadiran ke kelas tambahan ialah 6 orang setiap minggu."
(i) Hitung min kehadiran jika data minggu ketujuh diabaikan.
(ii) Adakah kenyataan Cikgu Rina menggambarkan kehadiran yang biasa? Nyatakan ukuran sukatan memusat yang lebih sesuai dan berikan satu alasan.Cikgu Rina says, "The average attendance at the extra class is 6 students each week."
(i) Calculate the mean attendance if the data for the seventh week is left out.
(ii) Does Cikgu Rina's statement describe the usual attendance? State the measure of central tendency that is more suitable and give one reason.
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For the teacher: Evaluating, high difficulty, Chapter 12, standard 12.1.5
Textbook p. 262
Test specification (JSU)
ChapterRememberingUnderstandingApplyingAnalysingEvaluatingCreatingItemsmarks
1. Patterns and Sequences–2 (5)––––25
2. Factorisation and Algebraic Fractions––2 (11)1 (1)––312
3. Algebraic Formulae––2 (11)–––211
4. Polygon––3 (6)–––36
5. Circles––2 (2)–1 (10)–312
6. Three-Dimensional Geometrical Shapes1 (1)–1 (1)–––22
7. Coordinates––3 (6)–––36
8. Graphs of Functions–1 (1)1 (10)–––211
9. Speed and Acceleration––1 (1)–––11
10. Gradient of a Straight Line––2 (5)–––25
11. Isometric Transformations––3 (12)–––312
12. Measures of Central Tendencies–––1 (1)1 (10)–211
13. Simple Probability––1 (1)1 (1)1 (4)–36
Total1 (1)3 (6)21 (66)3 (3)3 (24)0 (0)31100
Each cell shows items (marks).