Practice paper, not an official KPM paper

Peperiksaan Percubaan SPM (Model)SPM Trial Examination (Model)

KimiaChemistry

Tingkatan 5, 2 jam / 2 hours, 100 marks

Nama / Name

Kelas / Class

Tarikh / Date

Markah / Marks: / 100

Instructions

Kertas soalan ini mengandungi empat bahagian: Bahagian A, Bahagian B, Bahagian C dan Bahagian D.This question paper consists of four sections: Section A, Section B, Section C and Section D.
Bahagian A: pilih satu jawapan bagi setiap soalan. Bahagian B: jawab semua soalan. Bahagian C: jawab satu soalan sahaja. Bahagian D: soalan mesti dijawab.Section A: choose one answer for each question. Section B: answer all questions. Section C: answer one question only. Section D: this question must be answered.
Kerja mengira anda mesti ditunjukkan.Your working must be shown.
Rajah yang mengiringi soalan tidak dilukis mengikut skala kecuali dinyatakan.The diagrams are not drawn to scale unless stated.
Jawapan boleh ditulis dalam Bahasa Melayu atau Bahasa Inggeris.Answers may be written in Bahasa Melayu or English.
Jadual Berkala Unsur dan kalkulator saintifik dibenarkan.The Periodic Table and a scientific calculator are allowed.

Answer schemes are in English (DLP).

Practice shows answers as you go. Exam times you and hides answers until you submit.

Bahagian ASection A

20 marks

Jawab semua soalan. Setiap soalan diikuti oleh empat pilihan jawapan, A, B, C dan D. Pilih satu jawapan sahaja.Answer all questions. Each question is followed by four options, A, B, C and D. Choose one answer only.

Apakah nombor pengoksidaan kromium dalam kalium dikromat(VI), K₂Cr₂O₇?What is the oxidation number of chromium in potassium dichromate(VI), K₂Cr₂O₇?

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K = +1 and O = -2, so 2(+1) + 2x + 7(-2) = 0 and x = +6. The roman numeral VI in the name also gives +6.

For the teacher: Remembering, low difficulty, Chapter 1, standard 1.1.1

Textbook p. 6

Magnesium yang terbakar terus menyala di dalam balang gas karbon dioksida.
2Mg + CO₂ → 2MgO + C
Bahan manakah ialah agen pengoksidaan?Magnesium continues to burn in a gas jar of carbon dioxide.
2Mg + CO₂ → 2MgO + C
Which substance is the oxidising agent?

CO₂
Mg
MgO
C

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CO₂ loses oxygen (carbon changes from +4 to 0), so it is reduced and is the oxidising agent. Mg gains oxygen, so it is the reducing agent.

For the teacher: Understanding, low difficulty, Chapter 1, standard 1.1.2

Textbook p. 12

Sebuah sel kimia dibina daripada separuh sel Mg²⁺/Mg (E° = -2.38 V) dan separuh sel Ni²⁺/Ni (E° = -0.25 V). Apakah terminal negatif dan voltan sel itu?A chemical cell is made from a Mg²⁺/Mg half-cell (E° = -2.38 V) and a Ni²⁺/Ni half-cell (E° = -0.25 V). What is the negative terminal and the voltage of the cell?

Nikel; 2.13 VNickel; 2.13 V
Nikel; 2.63 VNickel; 2.63 V
Magnesium; 2.63 V
Magnesium; 2.13 V

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Mg has the more negative E°, so it is the negative terminal. E°cell = (-0.25) - (-2.38) = +2.13 V. 2.63 V comes from adding the two values.

For the teacher: Applying, medium difficulty, Chapter 1, standard 1.3.1

Textbook p. 30

Asid sulfurik cair dielektrolisiskan dengan menggunakan elektrod karbon. Pernyataan manakah betul tentang gas yang terkumpul?Dilute sulphuric acid is electrolysed using carbon electrodes. Which statement about the gases collected is correct?

Hidrogen terkumpul di anod.Hydrogen is collected at the anode.
Isi padu hidrogen di katod ialah dua kali isi padu oksigen di anod.The volume of hydrogen at the cathode is twice the volume of oxygen at the anode.
Isi padu hidrogen dan oksigen yang terkumpul adalah sama.Equal volumes of hydrogen and oxygen are collected.
Sulfur dioksida dibebaskan di anod.Sulphur dioxide is released at the anode.

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Cathode: 2H⁺ + 2e⁻ → H₂. Anode: 4OH⁻ → O₂ + 2H₂O + 4e⁻. For the same 4 mol of electrons, 2 mol of H₂ form for every 1 mol of O₂, so the volume ratio is 2 : 1.

For the teacher: Understanding, medium difficulty, Chapter 1, standard 1.4.3

Textbook p. 40

Antara persamaan setengah berikut, yang manakah menunjukkan penurunan oksigen semasa pengaratan besi?Which half equation shows the reduction of oxygen during the rusting of iron?

Fe → Fe²⁺ + 2e⁻
4OH⁻ → O₂ + 2H₂O + 4e⁻
O₂ + 2H₂O + 4e⁻ → 4OH⁻
Fe²⁺ → Fe³⁺ + e⁻

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Reduction is gain of electrons: oxygen gains electrons to form hydroxide ions at the cathode region. A and D are oxidations of iron; B is the oxidation of hydroxide ions in electrolysis.

For the teacher: Remembering, low difficulty, Chapter 1, standard 1.6.2

Textbook p. 55

Jadual menunjukkan keputusan apabila logam P, Q, R dan S dimasukkan ke dalam larutan nitrat logam lain. Pasangan elektrod manakah memberi voltan sel kimia paling tinggi dan yang manakah terminal negatif?

Logam	P²⁺	Q²⁺	R²⁺	S²⁺
P	-	bertindak balas	bertindak balas	bertindak balas
Q	tiada perubahan	-	bertindak balas	bertindak balas
R	tiada perubahan	tiada perubahan	-	bertindak balas
S	tiada perubahan	tiada perubahan	tiada perubahan	-

The table shows the results when metals P, Q, R and S are placed in nitrate solutions of the other metals. Which pair of electrodes gives the highest cell voltage, and which is the negative terminal?

Metal	P²⁺	Q²⁺	R²⁺	S²⁺
P	-	reacts	reacts	reacts
Q	no change	-	reacts	reacts
R	no change	no change	-	reacts
S	no change	no change	no change	-

P dan S; PP and S; P
P dan S; SP and S; S
Q dan R; QQ and R; Q
R dan S; SR and S; S

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P displaces all the others, S displaces none, so the order of reactivity is P > Q > R > S. The cell voltage is greatest for the two metals furthest apart, P and S. The more reactive metal, P, is the negative terminal.

For the teacher: Analysing, high difficulty, Chapter 1, standard 1.2.2

Textbook p. 25

Sebatian manakah ialah ahli siri homolog yang sama dengan CH₃CH₂CH₂OH?Which compound is a member of the same homologous series as CH₃CH₂CH₂OH?

CH₃CH₂COOH
CH₃CH₂CH₂CH₂OH
CH₃COOCH₃
CH₃CH=CH₂

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CH₃CH₂CH₂OH is propan-1-ol, an alcohol (-OH group). Butan-1-ol has the same functional group. A is a carboxylic acid, C an ester and D an alkene.

For the teacher: Remembering, low difficulty, Chapter 2, standard 2.2.1

Textbook p. 74

Etanol dihasilkan secara industri daripada etena dan stim. Apakah keadaan yang digunakan?Ethanol is manufactured industrially from ethene and steam. Which conditions are used?

Mangkin nikel, 180 °C, 1 atmNickel catalyst, 180 °C, 1 atm
Mangkin platinum, 25 °C, 1 atmPlatinum catalyst, 25 °C, 1 atm
Yis, 35 °C, tanpa oksigenYeast, 35 °C, no oxygen
Asid fosforik, 300 °C, 60 atmPhosphoric acid, 300 °C, 60 atm

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Hydration of ethene: steam, phosphoric acid catalyst, 300 °C, 60 atm. Nickel at 180 °C is for hydrogenation and yeast is for fermentation of glucose.

For the teacher: Remembering, low difficulty, Chapter 2, standard 2.3.1

Textbook p. 90

Berapakah jisim karbon dioksida yang terhasil apabila 4.6 g etanol, C₂H₅OH, terbakar lengkap dalam oksigen berlebihan? [Jisim atom relatif: H = 1, C = 12, O = 16]What is the mass of carbon dioxide formed when 4.6 g of ethanol, C₂H₅OH, burns completely in excess oxygen? [Relative atomic mass: H = 1, C = 12, O = 16]

4.4 g
6.6 g
8.8 g
13.2 g

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C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O. Moles of ethanol = 4.6 ÷ 46 = 0.1 mol. Moles of CO₂ = 0.2 mol. Mass = 0.2 × 44 = 8.8 g.

For the teacher: Applying, medium difficulty, Chapter 2, standard 2.3.1

Textbook p. 80

Propan-1-ol dioksidakan oleh kalium manganat(VII) berasid untuk menghasilkan sebatian Y. Sebatian Y kemudian bertindak balas dengan propan-1-ol dengan kehadiran asid sulfurik pekat untuk menghasilkan ester Z. Apakah formula molekul bagi Z?Propan-1-ol is oxidised by acidified potassium manganate(VII) to give compound Y. Compound Y then reacts with propan-1-ol in the presence of concentrated sulphuric acid to give ester Z. What is the molecular formula of Z?

C₆H₁₂O₂
C₅H₁₀O₂
C₆H₁₄O₂
C₃H₆O₂

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Y is propanoic acid, C₃H₆O₂. Z = C₃H₆O₂ + C₃H₈O - H₂O = C₆H₁₂O₂ (propyl propanoate). B is the formula you get from ethanoic acid and propan-1-ol; D is Y itself.

For the teacher: Analysing, high difficulty, Chapter 2, standard 2.3.2

Textbook p. 98

Apakah nama IUPAC bagi sebatian yang mempunyai formula struktur CH₃CH(CH₃)CH₂CH₃?What is the IUPAC name of the compound with the structural formula CH₃CH(CH₃)CH₂CH₃?

3-metilbutana3-methylbutane
2-etilpropana2-ethylpropane
2-metilpentana2-methylpentane
2-metilbutana2-methylbutane

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The longest chain has 4 carbon atoms (butane) with a methyl branch on carbon 2 (numbered from the end that gives the lowest number): 2-methylbutane.

For the teacher: Understanding, low difficulty, Chapter 2, standard 2.4.2

Textbook p. 104

Antara tindak balas berikut, yang manakah eksotermik?Which of the following reactions is exothermic?

Fotosintesis dalam daunPhotosynthesis in a leaf
Pembakaran gas asliCombustion of natural gas
Penguraian terma batu kapurThermal decomposition of limestone
Pelarutan ammonium klorida dalam airDissolving ammonium chloride in water

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Burning fuels releases heat (exothermic). Photosynthesis absorbs light energy, heating limestone to decompose it absorbs heat, and dissolving ammonium chloride makes the water colder (all endothermic).

For the teacher: Remembering, low difficulty, Chapter 3, standard 3.1.1

Textbook p. 116

Rajah 1 menunjukkan gambar rajah aras tenaga bagi tindak balas A → B. Pernyataan manakah betul?Diagram 1 shows the energy level diagram for the reaction A → B. Which statement is correct?

Rajah 1Diagram 1

Suhu bahan sekeliling meningkat.The temperature of the surroundings rises.
Tenaga yang dibebaskan semasa pembentukan ikatan dalam B lebih besar daripada tenaga yang diserap untuk memutuskan ikatan dalam A.The energy released when bonds in B form is greater than the energy absorbed to break the bonds in A.
Tenaga yang diserap untuk memutuskan ikatan dalam A lebih besar daripada tenaga yang dibebaskan semasa pembentukan ikatan dalam B.The energy absorbed to break the bonds in A is greater than the energy released when bonds in B form.
Kandungan tenaga A lebih tinggi daripada kandungan tenaga B.The energy content of A is higher than the energy content of B.

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B is higher than A and ΔH is positive, so the reaction is endothermic. More energy is absorbed to break bonds than is released on forming bonds, and the surroundings get colder.

For the teacher: Understanding, medium difficulty, Chapter 3, standard 3.1.2

Textbook p. 118

50 cm³ asid etanoik 1.0 mol dm⁻³ ditambah kepada 50 cm³ larutan natrium hidroksida 1.0 mol dm⁻³ pada suhu awal yang sama. Suhu campuran meningkat sebanyak 6.2 °C. Apakah haba peneutralan dan mengapakah nilainya lebih rendah daripada -57 kJ mol⁻¹ bagi asid hidroklorik dan natrium hidroksida? [Muatan haba tentu larutan = 4.2 J g⁻¹ °C⁻¹; ketumpatan larutan = 1 g cm⁻³]50 cm³ of 1.0 mol dm⁻³ ethanoic acid is added to 50 cm³ of 1.0 mol dm⁻³ sodium hydroxide solution at the same initial temperature. The temperature of the mixture rises by 6.2 °C. What is the heat of neutralisation, and why is it lower than -57 kJ mol⁻¹ for hydrochloric acid with sodium hydroxide? [Specific heat capacity of solution = 4.2 J g⁻¹ °C⁻¹; density of solution = 1 g cm⁻³]

-26.0 kJ mol⁻¹; asid etanoik ialah asid lemah dan sebahagian haba diserap untuk mengion sepenuhnya.-26.0 kJ mol⁻¹; ethanoic acid is a weak acid and some heat is absorbed to ionise it completely.
-26.0 kJ mol⁻¹; asid etanoik mempunyai bilangan atom hidrogen yang lebih sedikit.-26.0 kJ mol⁻¹; ethanoic acid has fewer hydrogen atoms.
-52.1 kJ mol⁻¹; asid etanoik ialah asid kuat yang mengion sepenuhnya dalam air.-52.1 kJ mol⁻¹; ethanoic acid is a strong acid that ionises completely in water.
-52.1 kJ mol⁻¹; asid etanoik ialah asid lemah dan sebahagian haba diserap untuk mengion sepenuhnya.-52.1 kJ mol⁻¹; ethanoic acid is a weak acid and some heat is absorbed to ionise it completely.

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Q = 100 × 4.2 × 6.2 = 2604 J. Moles of water formed = 1.0 × 50 ÷ 1000 = 0.050 mol. ΔH = -2.604 ÷ 0.050 = -52.1 kJ mol⁻¹. A weak acid ionises only partly, and some of the heat released is used to ionise it completely. -26.0 comes from dividing by 0.10 mol.

For the teacher: Analysing, high difficulty, Chapter 3, standard 3.2.3

Textbook p. 131

Bahan manakah digunakan sebagai agen pemvulkanan getah asli?Which substance is used as the vulcanising agent for natural rubber?

Larutan ammoniaAmmonia solution
SulfurSulphur
Asid metanoikMethanoic acid
Hidrogen peroksidaHydrogen peroxide

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Sulphur forms cross-links between rubber chains during vulcanisation. Ammonia stops coagulation and methanoic acid causes coagulation of latex.

For the teacher: Remembering, low difficulty, Chapter 4, standard 4.2.3

Textbook p. 156

Propena, CH₃CH=CH₂, mengalami pempolimeran penambahan untuk membentuk polipropena. Apakah unit ulangan bagi polimer ini?Propene, CH₃CH=CH₂, undergoes addition polymerisation to form polypropene. What is the repeat unit of this polymer?

-CH₂-CH(CH₃)-
-CH₂-CH₂-CH₂-
-CH₂-CH₂-
-CH(CH₃)-CH(CH₃)-

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The C=C double bond opens and the two carbon atoms join the chain, so the CH₃ group stays as a side group: -CH₂-CH(CH₃)-. C is the repeat unit of polythene.

For the teacher: Applying, medium difficulty, Chapter 4, standard 4.1.2

Textbook p. 146

Jadual menunjukkan pemanjangan empat keping getah yang mengandungi peratusan sulfur yang berbeza apabila diberi beban yang sama.

Peratusan sulfur (%)	1	3	8	30
Pemanjangan (cm)	14.0	9.5	4.0	0.2

Apakah kesimpulan yang betul?The table shows the extension of four pieces of rubber containing different percentages of sulphur under the same load.

Percentage of sulphur (%)	1	3	8	30
Extension (cm)	14.0	9.5	4.0	0.2

Which conclusion is correct?

Getah menjadi lebih kenyal apabila peratusan sulfur bertambah.The rubber becomes more elastic as the percentage of sulphur increases.
Getah dengan 30% sulfur mempunyai ikatan silang yang paling sedikit.The rubber with 30% sulphur has the fewest cross-links.
Peratusan sulfur yang lebih tinggi membentuk lebih banyak ikatan silang, maka getah lebih keras dan kurang memanjang.A higher percentage of sulphur forms more cross-links, so the rubber is harder and stretches less.
Sulfur tidak mempengaruhi pemanjangan getah.Sulphur does not affect the extension of the rubber.

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The extension falls from 14.0 cm to 0.2 cm as sulphur rises. More sulphur means more cross-links between the chains, so the chains slide past each other less and the rubber is harder.

For the teacher: Analysing, medium difficulty, Chapter 4, standard 4.2.4

Textbook p. 157

Aspirin ialah contoh ubat jenis apa?Aspirin is an example of which type of medicine?

AntibiotikAntibiotic
AntihistaminAntihistamine
Ubat psikotikPsychotic medicine
AnalgesikAnalgesic

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Aspirin, paracetamol and codeine are analgesics: they relieve pain.

For the teacher: Remembering, low difficulty, Chapter 5, standard 5.4

Textbook p. 182

Setiap molekul sejenis minyak sayuran mengandungi tiga ikatan ganda dua C=C secara keseluruhan. Berapakah mol hidrogen yang diperlukan untuk menepukan 1 mol minyak itu dengan mangkin nikel?Each molecule of a vegetable oil contains three C=C double bonds in total. How many moles of hydrogen are needed to saturate 1 mol of the oil with a nickel catalyst?

1 mol
3 mol
6 mol
9 mol

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Each C=C double bond adds one H₂ molecule, so 3 double bonds need 3 mol of H₂ per mol of oil. 6 mol would be needed if each double bond used two H₂, which is wrong.

For the teacher: Applying, medium difficulty, Chapter 5, standard 5.1

Textbook p. 167

Langkah-langkah rawatan air sisa industri secara pengelektrogumpalan ialah P: pengenapan kepingan gumpalan, Q: penyaringan sisa pepejal, R: pengelektrogumpalan, S: pengumpulan enapcemar. Antara berikut, yang manakah ialah urutan yang betul?The steps in treating industrial wastewater by electrocoagulation are P: settling of the flocs, Q: screening of solid waste, R: electrocoagulation, S: collection of sludge. Which is the correct sequence?

Q, R, P, S
R, Q, P, S
Q, P, R, S
Q, R, S, P

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Solid waste is screened out first (Q), then the wastewater is electrolysed so pollutants form flocs (R), the flocs settle (P) and the sludge is collected (S).

For the teacher: Understanding, low difficulty, Chapter 5, standard 5.6

Textbook p. 194

Bahagian BSection B

40 marks

Jawab semua soalan. Tulis jawapan anda di ruang yang disediakan.Answer all questions. Write your answers in the spaces provided.

Bahagian CSection C

20 marks

Jawab satu soalan sahaja. Setiap soalan bernilai 20 markah.Answer one question only. Each question carries 20 marks.

Bahagian DSection D

20 marks

Soalan ini mesti dijawab.This question must be answered.

Satu eksperimen dijalankan untuk menentukan haba pemendakan argentum klorida. 50 cm³ larutan argentum nitrat 1.0 mol dm⁻³ dicampurkan dengan 50 cm³ larutan natrium klorida 1.0 mol dm⁻³ dalam cawan polistirena. Keputusan ditunjukkan dalam jadual.

Suhu awal larutan argentum nitrat	29.0 °C
Suhu awal larutan natrium klorida	29.0 °C
Suhu tertinggi campuran	36.8 °C

[Muatan haba tentu larutan = 4.2 J g⁻¹ °C⁻¹; ketumpatan larutan = 1 g cm⁻³]An experiment is carried out to determine the heat of precipitation of silver chloride. 50 cm³ of 1.0 mol dm⁻³ silver nitrate solution is mixed with 50 cm³ of 1.0 mol dm⁻³ sodium chloride solution in a polystyrene cup. The results are shown in the table.

Initial temperature of silver nitrate solution	29.0 °C
Initial temperature of sodium chloride solution	29.0 °C
Highest temperature of the mixture	36.8 °C

[Specific heat capacity of solution = 4.2 J g⁻¹ °C⁻¹; density of solution = 1 g cm⁻³]

[2 marks] (a)Tulis persamaan ion bagi pemendakan argentum klorida dan nyatakan pemerhatian.Write the ionic equation for the precipitation of silver chloride and state the observation.

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Ag⁺(aq) + Cl⁻(aq) → AgCl(s) [1]1
A white precipitate forms [1]1

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[1 mark] (b)Mengapakah cawan polistirena digunakan dan bukannya bikar kaca?Why is a polystyrene cup used instead of a glass beaker?

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Polystyrene is a poor conductor of heat, so less heat is lost to the surroundings1

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[1 mark] (c)Hitung bilangan mol argentum klorida yang terbentuk.Calculate the number of moles of silver chloride formed.

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1.0 × 50 ÷ 1000 = 0.05 mol1

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[2 marks] (d)Hitung haba yang dibebaskan dalam eksperimen ini.Calculate the heat released in this experiment.

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Temperature rise = 36.8 - 29.0 = 7.8 °C [1]1
Q = 100 × 4.2 × 7.8 = 3276 J (3.28 kJ) [1]1

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[2 marks] (e)Hitung haba pemendakan argentum klorida dalam kJ mol⁻¹.Calculate the heat of precipitation of silver chloride in kJ mol⁻¹.

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3.276 kJ ÷ 0.05 mol [1]1
ΔH = -65.5 kJ mol⁻¹ [1]1

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[3 marks] (f)Lukis gambar rajah aras tenaga bagi tindak balas ini. Labelkan paksi, bahan tindak balas, hasil dan nilai ΔH.Draw the energy level diagram for this reaction. Label the axis, the reactants, the product and the value of ΔH.

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Energy axis, and Ag⁺(aq) + Cl⁻(aq) shown on the higher level [1]1
AgCl(s) on the lower level [1]1
Arrow downwards labelled ΔH = -65.5 kJ mol⁻¹ [1]1

Tick each point you got.

[3 marks] (g)Eksperimen diulang dengan menggunakan 50 cm³ argentum nitrat 0.5 mol dm⁻³ dan 50 cm³ natrium klorida 0.5 mol dm⁻³. Ramalkan kenaikan suhu, terangkan jawapan anda dan nyatakan haba pemendakan yang diperoleh.The experiment is repeated using 50 cm³ of 0.5 mol dm⁻³ silver nitrate and 50 cm³ of 0.5 mol dm⁻³ sodium chloride. Predict the temperature rise, explain your answer and state the heat of precipitation obtained.

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Temperature rise = 3.9 °C (half of 7.8 °C) [1]1
Number of moles of AgCl is halved (0.025 mol) so half the heat is released into the same mass of solution [1]1
Heat of precipitation is the same, -65.5 kJ mol⁻¹, because it is the heat change per mole [1]1

Tick each point you got.

[6 marks] (h)Rancangkan satu eksperimen makmal untuk membandingkan haba pembakaran metanol, etanol dan propan-1-ol. Jawapan anda mesti mengandungi pemboleh ubah, prosedur dan keputusan yang dijangka.Plan a laboratory experiment to compare the heat of combustion of methanol, ethanol and propan-1-ol. Your answer must include the variables, the procedure and the expected result.

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Manipulated variable: type of alcohol; responding variable: temperature rise of the water; fixed variables: volume (mass) of water, initial temperature of water, distance between the flame and the can2
Procedure: pour 100 cm³ of water into a copper can and record its initial temperature [1]1
Burn a spirit lamp containing methanol under the can while stirring; when the temperature has risen by about 30 °C put out the flame, record the highest temperature and the mass of the lamp before and after [1]1
Repeat with ethanol and propan-1-ol using fresh water at the same starting temperature [1]1
Expected result: heat of combustion (heat released per mole) increases from methanol to ethanol to propan-1-ol, because the number of carbon atoms per molecule increases so more heat is released [1]1

Tick each point you got.

For the teacher: Evaluating, high difficulty, Chapter 3, standard 3.2.1

Textbook p. 122

Test specification (JSU)

Chapter	Remembering	Understanding	Applying	Analysing	Evaluating	Creating	Items	marks
1. Redox equilibrium	2 (2)	2 (2)	2 (11)	1 (1)	1 (20)	–	8	36
2. Carbon compound	3 (11)	1 (1)	1 (1)	1 (1)	1 (20)	–	7	34
3. Thermochemistry	1 (1)	1 (1)	1 (8)	1 (1)	1 (20)	–	5	31
4. Polymer	1 (1)	–	2 (7)	1 (1)	–	–	4	9
5. Consumer and industrial chemistry	1 (1)	2 (8)	1 (1)	–	–	–	4	10
Total	8 (16)	6 (12)	7 (28)	4 (4)	3 (60)	0 (0)	28	120

Each cell shows items (marks).

KimiaChemistry

Bahagian ASection A

Question 1

Question 2

Question 3

Question 4

Question 5

Question 6

Question 7

Question 8

Question 9

Question 10

Question 11

Question 12

Question 13

Question 14

Question 15

Question 16

Question 17

Question 18

Question 19

Question 20

Bahagian BSection B

Question 21

Question 22

Question 23

Question 24

Question 25

Bahagian CSection C

Question 26

Question 27

Bahagian DSection D

Question 28