myUASARevision for UASA
Mathematics questions, unit 1

Whole Numbers and Operations

45 marks. Use Practice to check each answer as you go, or Exam to answer everything first.

Section A: objective questions

10 marks
Choose the correct answer.
1

Question 1

Which numeral is five million sixty thousand four hundred and nine?
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B
5 millions, 0 hundred thousands, 6 ten thousands, 0 thousands, 4 hundreds, 0 tens and 9 ones = 5 060 409.
For the teacher: Remembering, low difficulty, standard 1.1.1
Textbook p. 3
2

Question 2

What is the digit value of 3 in 8 035 214?
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D
The 3 is in the ten thousands place (8 | 0 | 3 | 5 | 2 | 1 | 4), so its digit value is 30 000.
For the teacher: Remembering, low difficulty, standard 1.1.1
Textbook p. 3
3

Question 3

Convert 2.35 million to a whole number.
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A
2.35 × 1 000 000 = 2 350 000.
For the teacher: Understanding, low difficulty, standard 1.1.5
Textbook p. 11
4

Question 4

Diagram 1 shows a number line. Each small step is 0.1 million. What is the value of P as a whole number?
Number line from 2 million to 3 million in 10 steps, point P at the sixth mark after 2 million
Diagram 1
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C
P is 6 steps after 2 million: 2 + 6 × 0.1 = 2.6 million = 2 600 000.
For the teacher: Understanding, medium difficulty, standard 1.1.4
Textbook p. 9
5

Question 5

1 250 000 + 0.75 million = ______
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B
0.75 million = 750 000. 1 250 000 + 750 000 = 2 000 000.
For the teacher: Applying, medium difficulty, standard 1.2.1
Textbook p. 16
6

Question 6

Calculate 8 × 0.45 million. Give the answer as a whole number.
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D
8 × 0.45 = 3.6, so the answer is 3.6 million = 3 600 000.
For the teacher: Applying, low difficulty, standard 1.2.1
Textbook p. 23
7

Question 7

The number pattern is 4 120 500, 4 320 500, 4 520 500, 4 720 500, ... Which statement is true?
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A
4 320 500 − 4 120 500 = 200 000. The numbers get bigger, so the pattern is ascending by two hundred thousands.
For the teacher: Understanding, low difficulty, standard 1.1.2
Textbook p. 5
8

Question 8

(9.6 million − 4 000 000) ÷ 8 = ______
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C
Brackets first: 9 600 000 − 4 000 000 = 5 600 000. Then 5 600 000 ÷ 8 = 700 000.
For the teacher: Applying, medium difficulty, standard 1.2.1
Textbook p. 34
9

Question 9

Which of these is a prime number?
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C
51 = 3 × 17, 57 = 3 × 19 and 63 = 7 × 9 are composite. 59 can be divided only by 1 and 59.
For the teacher: Understanding, medium difficulty, standard 1.3.1
Textbook p. 43
10

Question 10

k + 3 × 0.2 million = 1.1 million. What is the value of k?
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B
Multiply first: 3 × 0.2 million = 0.6 million. k = 1.1 million − 0.6 million = 0.5 million.
For the teacher: Analysing, high difficulty, standard 1.2.1
Textbook p. 38

Section B: structured questions

35 marks
Answer all questions. Show your working.
11

Question 11

Write the numbers.
[1 mark] (a)Write 6 070 308 in words.
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[1 mark] (b)Write nine million two hundred and five thousand and forty in numerals.
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For the teacher: Remembering, low difficulty, standard 1.1.1
Textbook p. 3
12

Question 12

Study the number 4 906 215.
[1 mark] (a)What is the digit value of the digit 4?
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[1 mark] (b)Partition the number by digit value.
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For the teacher: Understanding, low difficulty, standard 1.1.1
Textbook p. 3
13

Question 13

Diagram 2 shows a number pattern.
Number boxes: 3 405 120, 3 407 620, 3 410 120, blank, 3 415 120, blank
Diagram 2
[2 marks] (a)Fill in the two empty boxes.
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[1 mark] (b)State the number pattern.
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For the teacher: Applying, low difficulty, standard 1.1.2
Textbook p. 5
14

Question 14

Complete each conversion.
[1 mark] (a)0.8 million = ______ (whole number)
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[1 mark] (b)2¼ million = ______ (whole number)
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[1 mark] (c)4 500 000 = ______ (decimal of a million)
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[1 mark] (d)1 750 000 = ______ (fraction of a million, simplest form)
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For the teacher: Understanding, low difficulty, standard 1.1.5
Textbook p. 13
15

Question 15

The table shows the population of three towns.
TownPopulation
Bandar Jaya1 205 340
Seri Muda0.93 million
Tanjung Baru23⁄10 million
[2 marks] (a)Find the total population of the three towns. Give the answer as a whole number.
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[2 marks] (b)How many more people live in the largest town than in the smallest town?
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For the teacher: Applying, medium difficulty, standard 1.2.1
Textbook p. 15
16

Question 16

Calculate.
[2 marks] (a)5.2 million − 3 × 0.9 million. Give the answer in decimal of a million.
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[2 marks] (b)(1.8 million + 2⅕ million) ÷ 8. Give the answer as a whole number.
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For the teacher: Applying, medium difficulty, standard 1.2.1
Textbook p. 32
17

Question 17

Find the value of the unknown.
[2 marks] (a)p − 0.35 million = 1.2 million. Give p as a whole number.
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[2 marks] (b)(m + 0.04 million) × 5 = 400 000
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For the teacher: Applying, medium difficulty, standard 1.2.1
Textbook p. 40
18

Question 18

Diagram 3 shows six number cards.
Six number cards: 29, 37, 45, 49, 51, 61
Diagram 3
[1 mark] (a)Write all the prime numbers on the cards.
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[2 marks] (b)Aina takes a composite number and Raj takes a prime number. The difference between their numbers is 14. What number does Aina take?
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For the teacher: Analysing, medium difficulty, standard 1.4.1
Textbook p. 46
19

Question 19

Siti says: "13⁄5 million is 1 350 000, because 3⁄5 is 35."
[1 mark] (a)Is Siti correct?
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No
⅗ is 0.6, not 0.35.
[2 marks] (b)Explain her mistake and give the correct whole number.
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For the teacher: Evaluating, high difficulty, standard 1.1.5
Textbook p. 11
20

Question 20

A factory made 3.6 million pencils. The pencils were packed equally into 90 boxes.
[1 mark] (a)How many pencils are in one box?
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[1 mark] (b)A school bought 7 boxes. How many pencils did the school buy?
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[1 mark] (c)The school then received another 0.15 million pencils as a gift. How many pencils does the school have now?
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For the teacher: Applying, high difficulty, standard 1.4.1
Textbook p. 48
21

Question 21

Amir has seven digit cards. He uses all seven cards to make seven-digit numbers. A number cannot start with 0.
Digit cards 4, 0, 7, 3, 8, 5 and 1
Diagram 4
[1 mark] (a)What is the largest number he can make?
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[1 mark] (b)What is the smallest number he can make?
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[1 mark] (c)What is the smallest odd number he can make?
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For the teacher: Creating, high difficulty, standard 1.1.1
Textbook p. 3