Mathematics questions, chapter 4
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Polygon
44 marks. Use Practice to check each answer as you go, or Exam to answer everything first. The diagrams are drawn to scale, but you must calculate the angles, not measure them. Show your working for Section B.
Section A: objective questions
12 marksChoose the correct answer. Each question carries 1 mark.
1
Question 1
Which of the following is a regular polygon?
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C
A regular polygon has all sides equal and all interior angles equal. An equilateral triangle has three equal sides and three 60° angles. A rectangle has equal angles only, and a rhombus has equal sides only.
2
Question 2
How many axes of symmetry does a regular octagon have?
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B
A regular polygon has as many axes of symmetry as it has sides, so a regular octagon has 8. The number 16 comes from counting both ends of each axis.
3
Question 3
A rhombus that is not a square has four equal sides. Why is it not a regular polygon?
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B
A regular polygon needs equal sides and equal interior angles. A rhombus has equal sides, but its angles are not all equal (two are acute and two are obtuse). It does have 4 sides and 2 axes of symmetry.
4
Question 4
Find the sum of the interior angles of a decagon (10 sides).
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D
(10 − 2) × 180° = 8 × 180° = 1 440°. 1 800° forgets to subtract 2, and 1 260° and 1 620° use 7 and 9 triangles.
5
Question 5
What is the size of one interior angle of a regular nonagon (9 sides)?
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A
Exterior angle = 360° ÷ 9 = 40°, so the interior angle = 180° − 40° = 140°. 40° is the exterior angle, and 135° is the interior angle of an octagon.
6
Question 6
What is the exterior angle of a regular polygon with 18 sides?
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C
Exterior angle = 360° ÷ 18 = 20°. 160° is the interior angle (180° − 20°).
7
Question 7
The exterior angle of a regular polygon is 15°. How many sides does the polygon have?
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D
n = 360° ÷ 15° = 24. Check the others: 12 sides gives 30°, 15 sides gives 24° and 20 sides gives 18°.
8
Question 8
Diagram 1 shows a quadrilateral. Find the value of x.
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A
The interior angles of a quadrilateral add up to (4 − 2) × 180° = 360°. x = 360° − 85° − 110° − 70° = 95°. 265° is the total of the three given angles.
9
Question 9
In a regular polygon, each interior angle is 5 times the exterior angle. How many sides does the polygon have?
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C
Interior + exterior = 180° and interior = 5 × exterior, so 6 × exterior = 180° and exterior = 30°. n = 360° ÷ 30° = 12.
10
Question 10
What is the sum of the exterior angles of an octagon?
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A
The sum of the exterior angles of any polygon is 360°. 1 080° is the sum of the interior angles, and 45° is one exterior angle of a regular octagon.
11
Question 11
Diagram 2 shows a regular pentagon and a regular hexagon that share the side CD. Find the size of the angle at C between CB and CI (the angle that is outside both polygons).
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D
The angles at C add up to 360°. Interior angle of the pentagon = 108°; interior angle of the hexagon = 120°. The outside angle = 360° − 108° − 120° = 132°. 228° is 108° + 120°.
12
Question 12
Which of these angles cannot be an interior angle of a regular polygon?
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B
For 100° the exterior angle is 80° and n = 360 ÷ 80 = 4.5, which is not a whole number. 108° gives n = 5, 120° gives n = 6 and 140° gives n = 9.
Section B: structured questions
32 marksAnswer all questions. Show your working.
13
Question 13
A regular polygon has 12 sides.
[1 mark]
(a)State the name of the polygon.
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[1 mark]
(b)How many axes of symmetry does it have?
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[1 mark]
(c)Find the size of one exterior angle.
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[1 mark]
(d)Find the size of one interior angle.
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14
Question 14
Diagram 3 shows a pentagon.
[1 mark]
(a)Find the sum of the interior angles of a pentagon.
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[2 marks]
(b)Find the value of x.
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15
Question 15
Diagram 4 shows a hexagon with one side extended at every vertex. The exterior angles are 45°, 60°, 50°, 70°, x and 2x.
[1 mark]
(a)The sum of the exterior angles of this hexagon is
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360°
The exterior angles of any polygon add up to 360°. 720° is the sum of the interior angles of a hexagon.
[2 marks]
(b)Find the value of x.
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[1 mark]
(c)Find the interior angle at the vertex whose exterior angle is 2x.
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16
Question 16
In Diagram 5, ABCDEFGH is a regular octagon. AB is extended and DC is extended so that they meet at P.
[1 mark]
(a)Find the exterior angle of the octagon.
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[1 mark]
(b)State ∠PBC and ∠PCB.
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[1 mark]
(c)Find ∠BPC.
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[1 mark]
(d)What type of triangle is PBC?
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PB = PC because the base angles are equal.
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17
Question 17
Each interior angle of a regular polygon is 150°.
[1 mark]
(a)Find the exterior angle.
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[1 mark]
(b)Find the number of sides of the polygon.
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[2 marks]
(c)Find the sum of the interior angles of the polygon.
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Check: 12 × 150° = 1 800°.
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18
Question 18
The sum of the interior angles of a regular polygon is 3 240°.
[2 marks]
(a)Find the number of sides.
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[1 mark]
(b)State the name of this polygon.
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[1 mark]
(c)Find the size of one exterior angle.
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19
Question 19
In a regular polygon, an interior angle is (5y + 10)° and an exterior angle is (y + 20)°.
[2 marks]
(a)Find the value of y.
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[1 mark]
(b)Find the exterior angle and the interior angle.
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[2 marks]
(c)Find the number of sides and name the polygon.
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20
Question 20
Azreen designs a logo for her school club. It is a regular hexagon with the centre O joined to every vertex, as in Diagram 6. The distance from O to each vertex is 4 cm.
[1 mark]
(a)Find the angle at O between two neighbouring radii.
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[2 marks]
(b)Each triangle at the centre has two sides of 4 cm and an angle of 60° between them. What is the length of each side of the hexagon? Give a reason.
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[1 mark]
(c)Azreen draws the hexagon with compasses and a ruler. What should she set the compasses to, to mark the vertices round the circle?
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The side of a regular hexagon equals the radius of its circle.
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