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Mathematics questions, chapter 8

Graphs of Functions

42 marks. Use Practice to check each answer as you go, or Exam to answer everything first. Graph paper and a ruler are needed for question B5. Show your working for Section B.

Section A: objective questions

12 marks
Choose the correct answer. Each question carries 1 mark.
1

Question 1

Which statement describes a function?
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B
A function is a relation in which each object in the domain has only one image. Two objects may share an image (many-to-one), so "each image has one object" is not required. Objects with more than one image make the relation not a function.
For the teacher: Remembering, low difficulty, standard 8.1.1
Textbook p. 146
2

Question 2

Diagram 1 shows the relation "the square of" from set P to set Q. What type of relation is shown?
Arrow diagram: -2 and 2 are both mapped to 4; -1 and 1 are both mapped to 1; 9 in set Q has no arrow
Diagram 1
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D
Each object has only one image, but two objects share the same image (−2 and 2 both go to 4; −1 and 1 both go to 1). That is a many-to-one relation, which is a function.
For the teacher: Understanding, low difficulty, standard 8.1.1
Textbook p. 148
3

Question 3

Which set of ordered pairs is not a function?
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C
In {(2, 1), (2, 3), (4, 5)} the object 2 has two images, 1 and 3, so it is a one-to-many relation. In the other sets every first number appears only once, so each is a function (the first and last are many-to-one).
For the teacher: Applying, low difficulty, standard 8.1.2
Textbook p. 150
4

Question 4

The function f(x) = 2x + 3 has the domain {1, 2, 4}. What is the range?
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A
f(1) = 5, f(2) = 7 and f(4) = 2(4) + 3 = 11, so the range is {5, 7, 11}. {2, 4, 8} is the domain doubled (forgetting + 3), and {5, 7, 9} comes from using 3 for the last object instead of 4.
For the teacher: Applying, low difficulty, standard 8.1.2
Textbook p. 149
5

Question 5

Find the value of y when x = −2 for the function y = 2x² − 5.
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C
y = 2(−2)² − 5 = 2(4) − 5 = 3. −13 comes from treating (−2)² as −4. 11 comes from squaring 2 × (−2). −9 comes from not squaring: 2(−2) − 5.
For the teacher: Applying, low difficulty, standard 8.2.1
Textbook p. 151
6

Question 6

The graph of which function is a hyperbola (two separate branches)?
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D
y = 6x is a reciprocal function, and its graph is a hyperbola with two branches. y = 2x + 1 gives a straight line, y = x² − 4 a parabola and y = x³ + 2 a cubic curve.
For the teacher: Remembering, low difficulty, standard 8.2.1
Textbook p. 156
7

Question 7

Diagram 2 shows the graph of a function. Which function does it represent?
A U-shaped curve with its lowest point at (0, -4), crossing the x-axis at -2 and 2
Diagram 2
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A
The graph is a U-shaped parabola, so the function is quadratic. At x = 0, y = −4, and at x = 2, y = 4 − 4 = 0, which match y = x² − 4. 4 − x² would open downwards, and x² + 4 has its lowest point at (0, 4).
For the teacher: Understanding, medium difficulty, standard 8.2.1
Textbook p. 154
8

Question 8

Diagram 3 shows the graph of y = 2x − 2. Find the value of x when y = 6.
Straight line y = 2x - 2 on a grid from x = -1 to 6, crossing the x-axis at 1 and the y-axis at -2
Diagram 3
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B
Draw a line across from y = 6 to the graph, then down to the x-axis: x = 4. Check: 2(4) − 2 = 6. 10 is the value of y when x = 6, and 2 is the value of y when x = 2.
For the teacher: Applying, low difficulty, standard 8.2.2
Textbook p. 158
9

Question 9

Diagram 4 shows the graph of y = x² − 4x + 3. What are the values of x when y = 0?
Parabola y = x squared minus 4x plus 3 with lowest point (2, -1), crossing the x-axis at 1 and 3
Diagram 4
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D
y = 0 on the x-axis. The curve crosses the x-axis at x = 1 and x = 3. Check: 1 − 4 + 3 = 0 and 9 − 12 + 3 = 0. x = 2 is where the lowest point is, where y = −1.
For the teacher: Applying, medium difficulty, standard 8.2.2
Textbook p. 158
10

Question 10

Diagram 5 shows the charge, C (in RM), for parking a car for t hours. Mr Lim parks his car for 4 hours. How much does he pay?
Straight line from (0, 2) rising by 3 for every 1 hour, up to RM20 at 6 hours
Diagram 5
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A
At t = 4 the line is at C = 14, so he pays RM14. The line does not start at 0: there is a RM2 charge to enter, so 3 × 4 = 12 is not enough. RM11 is the charge for 3 hours.
For the teacher: Applying, low difficulty, standard 8.2.3
Textbook p. 160
11

Question 11

Diagram 6 shows the heights of two candles, A and B, that were lit at the same time. For which times is candle B taller than candle A?
Two falling straight lines. A starts at 20 cm and reaches 0 at 10 hours; B starts at 12 cm and reaches 0 at 12 hours. They cross at 8 hours at a height of 4 cm
Diagram 6
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B
The lines cross at (8, 4): both candles are 4 cm tall after 8 hours. Before that candle A is taller. Between 8 and 12 hours the line for B is above the line for A, so B is taller (at 10 hours A is 0 cm and B is 2 cm). After 12 hours both have burnt out.
For the teacher: Analysing, high difficulty, standard 8.2.3
Textbook p. 160
12

Question 12

Diagram 7 shows the height, h metres, of a ball t seconds after it is kicked. For how many seconds is the ball higher than 5 m?
Parabola h = 6t - t squared from (0, 0) up to a maximum of 9 at t = 3 and back to 0 at t = 6; the height is 5 at t = 1 and t = 5
Diagram 7
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B
The curve is at h = 5 when t = 1 and when t = 5 (check: 6 − 1 = 5 and 30 − 25 = 5). The ball is above 5 m from 1 s to 5 s, which is 5 − 1 = 4 seconds. 5 is only the second time the ball is at 5 m; 6 is the whole flight.
For the teacher: Analysing, high difficulty, standard 8.2.3
Textbook p. 161

Section B: structured questions

30 marks
Answer all questions. Show your working.
13

Question 13

Diagram 8 shows the function f that maps x to x + 4 from set A to set B.
Arrow diagram: 1 goes to 5, 2 goes to 6, 3 goes to 7; set B also contains 8, which receives no arrow
Diagram 8
[1 mark] (a)State the image of 3.
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[2 marks] (b)State the codomain and the range of the function.
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For the teacher: Understanding, low difficulty, standard 8.1.2
Textbook p. 149
14

Question 14

The function f is defined by f(x) = 2x − 1 for the domain P = {2, 3, 4, 5}.
[2 marks] (a)Write the function as a set of ordered pairs.
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[1 mark] (b)State the range of the function.
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For the teacher: Applying, low difficulty, standard 8.1.2
Textbook p. 150
15

Question 15

Diagram 9 shows two relations drawn as graphs of points.
Four points (1, 3), (2, 3), (3, 5) and (4, 5)
Graph (a)
Four points (1, 2), (1, 4), (2, 6) and (3, 7)
Graph (b)
[2 marks] (a)Is graph (a) a function? Give a reason.
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[2 marks] (b)Is graph (b) a function? Give a reason.
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For the teacher: Understanding, low difficulty, standard 8.1.2
Textbook p. 150
16

Question 16

The table shows some values of the function y = x² + x − 2.
x−3−2−1012
y4PQ−2R4
[2 marks] (a)Find the values of P, Q and R.
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[1 mark] (b)What is the shape of the graph of this function?
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[1 mark] (c)Find the value of y when x = 3.
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For the teacher: Applying, low difficulty, standard 8.2.1
Textbook p. 154
17

Question 17

Draw the graph of the function y = 2x − 3 for −1 ≤ x ≤ 3 on graph paper. Use a scale of 2 cm to 1 unit on both axes.
[2 marks] (a)Construct a table of values for x = −1, 0, 1, 2 and 3.
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[2 marks] (b)Draw the axes with the scale, plot the points and draw the graph.
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For the teacher: Applying, medium difficulty, standard 8.2.1
Textbook p. 153
18

Question 18

Diagram 10 shows the graph of the function y = 12x.
Hyperbola y = 12 over x: one branch in the top right through (2, 6), (3, 4), (6, 2); one branch in the bottom left through (-6, -2), (-4, -3), (-3, -4), (-2, -6)
Diagram 10
[1 mark] (a)From the graph, find the value of y when x = 3.
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[1 mark] (b)Find the value of x when y = 2.
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[1 mark] (c)Find the value of x when y = −3.
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For the teacher: Applying, low difficulty, standard 8.2.2
Textbook p. 158
19

Question 19

Diagram 11 shows the monthly cost of two prepaid phone plans, P and Q, for talk time of up to 40 minutes.
Two lines. Plan P starts at RM10 for 0 minutes and reaches RM30 at 40 minutes. Plan Q starts at RM0 and reaches RM40 at 40 minutes. They cross at 20 minutes, RM20
Diagram 11
[1 mark] (a)How much does each plan charge for 30 minutes of talk time?
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[1 mark] (b)For how many minutes of talk time is the cost the same for both plans?
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[1 mark] (c)Tina uses 40 minutes a month. Which plan should she choose, and how much will she save?
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[1 mark] (d)Rizal uses only 10 minutes a month. Which plan is cheaper for him? Explain.
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For the teacher: Analysing, medium difficulty, standard 8.2.3
Textbook p. 160
20

Question 20

Hana drew the graph of the function y = x² − 4 for −2 ≤ x ≤ 2. Diagram 12 shows her graph.
Five points (-2, 0), (-1, -3), (0, -4), (1, -3), (2, 0) joined by straight line segments forming a V shape
Diagram 12
[1 mark] (a)Hana's graph has a mistake in the way the points are joined. What is it?
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[1 mark] (b)Find the value of y when x = 3.
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[1 mark] (c)State the lowest value of y on the graph and the value of x where it happens.
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For the teacher: Evaluating, high difficulty, standard 8.2.1
Textbook p. 154
21

Question 21

A gym charges a joining fee of RM20 and RM10 for every visit. Let RMy be the total cost after x visits.
[1 mark] (a)Write a function that gives y in terms of x.
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[1 mark] (b)State the shape of the graph and give a reason.
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For the teacher: Creating, medium difficulty, standard 8.2.1
Textbook p. 152