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Chemistry notes, chapter 7

Rate of Reaction

Textbook Chemistry Form 4 KSSM (DLP), pages 218–251

What this chapter covers

  • Classify fast and slow reactions and explain the meaning of the rate of reaction (7.1)
  • Identify the changes that can be observed and measured during a reaction (7.1)
  • Calculate the average rate and the instantaneous rate of reaction from data and graphs (7.1)
  • Investigate how the size of reactants, concentration, temperature and a catalyst affect the rate of reaction (7.2)
  • Explain how the factors that affect the rate of reaction are applied in daily life (7.3)
  • Use the collision theory and activation energy to explain the rate of reaction (7.4)
  • Interpret energy profile diagrams of exothermic and endothermic reactions, with and without a catalyst (7.4)

7.1Determining rate of reaction

The rate of reaction is the change in the quantity of a reactant, or of a product, per unit time.

Some reactions are fast (ignition of matches, fireworks, combustion of gases, electric cells). Others are slow (rusting, food decay, photosynthesis, fermentation, erosion of rock).

Rate of reaction = change in the quantity of reactant or product ÷ time taken for the change.

Quantity measuredCommon units of rate
Mass of a solidg s−1 or g minute−1
Volume of a gascm3 s−1 or cm3 minute−1
Concentration of a solutionmol dm−3 s−1 or mol dm−3 minute−1

Changes you can observe and measure

ChangeExampleHow it is measured
Precipitate formsAgNO3 + NaCl gives AgClTime for a "X" mark to disappear; mass of precipitate
Mass of reactants decreasesHNO3 + CaCO3 releases CO2Electronic balance
Volume of gas increasesHCl + Mg releases H2Gas syringe or burette over water
Pressure changesReactions of gasesPressure meter
Electrical conductivity changesReactions with mobile ionsAmmeter
pH changesAcids or bases in solutionpH meter

Average rate and instantaneous rate

Average rate
The rate over a period of time. Overall average rate = total volume of gas ÷ time taken for the reaction to finish. For a period t1 to t2: (V2 − V1) ÷ (t2 − t1).
Instantaneous rate
The rate at one moment. Draw a tangent to the curve at that time. The rate is the gradient of the tangent, ΔV ÷ Δt. A bigger triangle gives a more accurate gradient.

Analogy: a car that covers 400 km in 4 hours has an average speed of 100 km h−1. A speed camera that reads 140 km h−1 gives the speed at that instant.

Worked example

Excess MgCO3 reacts with sulphuric acid. The volume of CO2 is recorded every minute (Table 7.2 in the textbook).

Time (minute)012345678910
Volume (cm3)025405158636870707070
Graph of volume of gas against time rising steeply at first, then levelling at 70 cm3 from 7 minutes
Volume of gas against time. The curve is steepest at the start and flat once the reaction stops.

Fifth minute (4th to 5th): (63 − 58) ÷ (5 − 4) = 5 cm3 minute−1.

Overall: the volume stops rising at 7 minutes, so 70 ÷ 7 = 10 cm3 minute−1.

For the overall average rate, divide by the time the reaction ended (7 minutes here), not the end of the recording (10 minutes).
A reaction releases 48 cm3 of gas in 4 minutes and then stops. Calculate the overall average rate.
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48 ÷ 4 = 12 cm3 minute−1.

7.2Factors affecting the rate of reaction

A catalyst is a substance that changes the rate of a reaction without itself being chemically changed at the end. It does not change the quantity of product.
FactorChangeEffect on rateExperiment in the textbook
Size of reactantSmaller pieces (larger total surface area)IncreasesMarble chips with HCl, volume of CO2 against time
ConcentrationHigher concentrationIncreasesNa2S2O3 with H2SO4, time for the "X" mark to disappear
TemperatureHigher temperatureIncreasesSame reaction from room temperature to 55 °C
CatalystCatalyst presentIncreasesH2O2 with MnO2, glowing splinter relights
Remember the four factors with CSTP: Concentration, Size of solid reactant, Temperature, Presence of catalyst. For gases, higher pressure also raises the rate because it raises the concentration.
  • For a fixed mass, a powder has a larger total surface area than a lump. Cutting a 2 cm cube into smaller pieces raises the total surface area (24 cm2 to 32 cm2 to 40 cm2 in the textbook figure).
  • In the sodium thiosulphate experiment, rate = 1 ÷ time. Graph the rate against concentration. At room temperature, a rise of 10 °C roughly doubles the rate.
  • A catalyst may change physically (a lump becomes powder) but its mass and chemical properties stay the same.
A change in rate does not change the total amount of product. If the reactants are the same, the final volume of gas is the same. Only the time to get there changes.
Worked example

Experiment I uses 1.0 mol dm−3 HCl and takes 120 s. Experiment II uses 2.0 mol dm−3 HCl and takes 60 s. Same antacid tablet, same temperature.

Rate = 1 ÷ time: I = 1 ÷ 120 = 0.0083 s−1; II = 1 ÷ 60 = 0.017 s−1. The higher concentration doubles the rate.

Name the manipulated and the responding variable in the experiment on the effect of temperature on the reaction of sodium thiosulphate with sulphuric acid.
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Manipulated: temperature of the sodium thiosulphate solution. Responding: time for the "X" mark to disappear (rate of reaction).

7.3Factors in daily life

FactorApplicationWhy it works
SizeChewing an antacid tablet; slicing potatoes thinly before fryingLarger total surface area exposed
ConcentrationIron corrodes faster near industry; petrol vapour compressed in a car engineMore acid rain pollutant; more particles per unit volume
TemperatureWashing with hot water and detergent; frying in oil above 100 °C; keeping food in a refrigeratorHigher temperature speeds reactions up; low temperature slows bacterial decay
CatalystPlatinum catalytic converter; yeast enzymes make ethanol at 37 °CPollutants (CO, NOx, hydrocarbons) become CO2, N2, H2O
Why does coal burn faster as small chips than as a large lump?
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Small chips have a larger total surface area exposed to oxygen, so collisions with oxygen are more frequent.

7.4Collision theory

The collision theory says that reactant particles must collide for a reaction to occur, and the rate depends on the frequency of effective collisions. A collision is effective only if the particles have energy ≥ the activation energy, Ea, and collide in the correct orientation.
Factor increasedWhat happens to the particles
Concentration or pressureMore particles per unit volume, so collisions are more frequent, so effective collisions are more frequent
Total surface areaMore particles exposed to collision, so effective collisions are more frequent
TemperatureParticles gain kinetic energy, more of them reach Ea, effective collisions are more frequent
CatalystAn alternative pathway with a lower activation energy Ea′, so more particles reach it

Energy profile diagrams

Energy profile of an exothermic reaction: reactants high, products lower, a peak between them marked Ea and an arrow down marked delta HExothermic
Reactants have more energy than products. Heat is released to the surroundings. ΔH is negative.
Energy profile of an endothermic reaction: reactants low, products higher, a peak marked Ea and an arrow up marked delta HEndothermic
Products have more energy than reactants. Heat is absorbed from the surroundings. ΔH is positive.
Exothermic energy profile with a second dashed lower peak showing a catalyst lowers the activation energy
A catalyst lowers the peak (Ea′ < Ea). ΔH stays the same.
A catalyst lowers the activation energy but does not change the energy of reactants or products, so ΔH is unchanged. Temperature does not lower Ea: it gives more particles energy ≥ Ea.
State two conditions for an effective collision.
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The particles have energy equal to or more than the activation energy, and they collide in the correct orientation.